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  • strcpy 一题

    题目要求:

    Write a function about string copy, the strcpy prototype is "char *strcpy (char *strDest, const char *strSrc); "

    Here strDest is destination string, strSrc is source string.

    1) Write the function strcpy, don't call C/C++ string library.

    2) Here strcpy can copy strSrc to strDest, but why we use char * as the return value of strcpy?

    问题解决:

    1)代码实现

    #include <stdio.h>
    #include <assert.h>
    
    char *sstrcpy(char *strdst, const char *strsrc)
    {
        assert(strdst != NULL && strsrc != NULL);
    
        char *ret_str = strdst;
        while ((*strdst++ = *strsrc++) != '');
        return ret_str;
    }
    
    int main(int argc, char **argv)
    {
        char dst[20] = {0};
        char *src = "abcde";
    
        printf("res = %s
    ", sstrcpy(dst, src));
    
        return 0;
    }

    2)返回字符串指针,是为了实现链式表达。Unix设计哲学思想。

    比如

    printf("res = %s
    ", sstrcpy(dst, src));
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  • 原文地址:https://www.cnblogs.com/aqing1987/p/4613706.html
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