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  • 1.求矩形面积

    public class juxing {
    
      double Chang;
        
         double Kuan;
    
        void M(double x1,double x2)
        {
            Chang = x1;
            
            Kuan=x2;
            
            double MianJi=Chang*Kuan;
            
            System.out.println("矩形的面积="+MianJi);
            
        }
        
        
             //属性
        double chang1=22;
        
        double kuai2=11;
        
        public double MJ(double c1,double v1)
        
        {
            double a =c1;
            
            double b =v1;
            
            return a*b;
            
    }
    
    
    public class ceshi {
    
        public static void main(String[] args) {
            
                juxing S=new juxing();
                
                S.M(23,11);
                
                   System.out.println("长方形的面积是"+S.Chang*S.Kuan);
    
                  
            
            
                   //新的面积
                   
                   juxing dx=new juxing();
                   
                   dx.MJ(33, 44);
                   
                   System.out.println("新1的面积是="+dx.chang1*dx.kuai2);
                   
                   System.out.println("新2的面积是="+dx.MJ(33, 44));
            }
    
        }

    矩形的面积=253.0
    长方形的面积是253.0
    新1的面积是=242.0
    新2的面积是=1452.0

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  • 原文地址:https://www.cnblogs.com/as1234as/p/5138246.html
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