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  • leetcode--Search in Rotated Sorted Array II

    Follow up for "Search in Rotated Sorted Array":
    What if duplicates are allowed?

    Would this affect the run-time complexity? How and why?

    Write a function to determine if a given target is in the array.

    public class Solution {
        public boolean search(int[] A, int target) {
    		boolean isIn = false;
    		int index = findMin(A);		
    		if(index == 0)
    			isIn = (Arrays.binarySearch(A, 0, A.length, target) >= 0);
    		else
    			isIn = (Arrays.binarySearch(A, 0, index, target) >= 0) 
    					|| (Arrays.binarySearch(A, index, A.length, target) >= 0);
    		return isIn;
    	}
    	public static int findMin(int[] A){
    		int i = A.length - 1;
    		for(; i > 0; --i){
    			if(A[i] < A[i - 1])
    				break;
    		}
    		return i;
        }
    }
    

      

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  • 原文地址:https://www.cnblogs.com/averillzheng/p/3774408.html
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