zoukankan      html  css  js  c++  java
  • 如何在java List中进行模糊查询

    比如我有下面这样一个List,里面存放的是多个Employee对象。然后我想对这个List进行按照Employee对象的名字进行模糊查询。有什么好的解决方案么?
    比如我输入的查询条件为“wang”,那么应该返回只包含employee1的List列表。

    List list = new ArrayList();
    Employee employee1 = new Employee();
    employee1.setName("wangqiang");
    employee1.setAge(30);
    list.add(employee1);
    Employee employee2 = new Employee();
    employee2.setName("lisi");
    list.add(employee2);
    employee2.setAge(25);

    方式一:

    public List search(String name,List list){
       List results = new ArrayList();
       Pattern pattern = Pattern.compile(name);
       for(int i=0; i < list.size(); i++){
          Matcher matcher = pattern.matcher(((Employee)list.get(i)).getName());
          if(matcher.matches()){
             results.add(list.get(i));
          }
       }
       return results;
    }

    上面那个是大小写敏感的,如果要求大小写不敏感,改成:
    Pattern pattern = Pattern.compile(name,Pattern.CASE_INSENSITIVE);

    并且上面那个是精确查询,如果要模糊匹配,matcher.find()即可以进行模糊匹配

    public List search(String name,List list){
       List results = new ArrayList();
       Pattern pattern = Pattern.compile(name);
       for(int i=0; i < list.size(); i++){
          Matcher matcher = pattern.matcher(((Employee)list.get(i)).getName());
          if(matcher.find()){
             results.add(list.get(i));
          }
       }
       return results;
    }

    方式二:

    public class ListLike {
    
    //定义员工类
    public class Employee {
    private String name;
    private int age;
    public int getAge() {
    return age;
    }
    public void setAge(int age) {
    this.age = age;
    }
    public String getName() {
    return name;
    }
    public void setName(String name) {
    this.name = name;
    }
    }
    
    public List list=new ArrayList();
    
    //增加员工
    public List addList(String name,int age){
    Employee employee1 = new Employee();
    employee1.setName(name);
    employee1.setAge(age);
    list.add(employee1);
    return list;
    }
    
    //显示所有员工
    public void ShowList(){
    for(int i=0;i<list.size();i++){
    System.out.println(((Employee)(list.get(i))).getName()+" "+((Employee)(list.get(i))).getAge());
    }
    }
    
    //模糊查询
    public List likeString(String likename){
    for(int i=0;i<list.size();i++){
    if(((Employee)(list.get(i))).getName().indexOf(likename)<=-1)
    list.remove(i);
    }
    return list;
    
    }
    
    public static void main(String arg[]){
    ListLike ll=new ListLike();
    ll.addList("wuxiao",13);
    ll.addList("wangwang",11);
    ll.addList("wanghua",12);
    ll.addList("xiaowang",13);
    ll.addList("xiaoxiao",13);
    
    ll.likeString("wang");
    ll.ShowList();
    
    
    }
    
    }




  • 相关阅读:
    Django----博客文章数据返回
    Django----admin模块初识
    Django搭建博客文章---模型层
    Js 提交 form 表单
    sql 查询 between and 和 >= <= 比较
    C# 未能加载项目文件
    不一样的 Null
    Js实现table单双行交替色
    C# 判断一个string型的时间格式是否正确
    利用 Label 小小的提升一下用户体验
  • 原文地址:https://www.cnblogs.com/azhqiang/p/5594447.html
Copyright © 2011-2022 走看看