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  • delphi 10.2 ----简单的递归函数例子求和

    unit Unit10;

    interface

    uses
    Winapi.Windows, Winapi.Messages, System.SysUtils, System.Variants, System.Classes, Vcl.Graphics,
    Vcl.Controls, Vcl.Forms, Vcl.Dialogs, Vcl.StdCtrls;

    type
    TForm10 = class(TForm)
    Edit1: TEdit;
    Edit2: TEdit;
    Edit3: TEdit;
    Edit4: TEdit;
    Label1: TLabel;
    Label2: TLabel;
    Label3: TLabel;
    Label4: TLabel;
    Edit5: TEdit;
    Label5: TLabel;
    Button1: TButton;
    function sum1(A:integer):integer;
    function xj(X,Y: integer):integer;
    procedure Button1Click(Sender: TObject);
    private
    { Private declarations }
    public
    { Public declarations }
    end;

    var
    Form10: TForm10;

    implementation

    {$R *.dfm}

    { TForm10 }

    procedure TForm10.Button1Click(Sender: TObject);
    begin
    if (Edit1.Text='') and (Edit3.Text='') then
    begin
    showmessage('请输入数字');
    EXIT; //退出message
    end;
    Edit2.Text:=intToStr(sum1(Strtoint((Edit1.Text))));
    Edit4.Text:=intToStr(sum1(Strtoint((Edit3.Text))));
    Edit5.Text:=IntToStr(xj(StrToint(Edit1.Text),StrToInt(Edit3.Text)));
    end;

    function TForm10.sum1(A: integer): integer; //求和函数
    var
    i,sum1:integer; //定义变量, i ,sum1
    begin
    sum1:=0;
    for i := 0 to A do
    sum1:=sum1+i;
    result:=sum1;

    end;

    function TForm10.xj(X, Y: integer): integer; //减法函数
    begin
    result:=sum1(x)-sum1(y);
    end;

    end.

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  • 原文地址:https://www.cnblogs.com/baili-luoyun/p/9804146.html
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