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  • POJ 2184 DP 01背包+完全背包

    链接:

    http://poj.org/problem?id=2184

    代码:

     1 #include <map>
     2 #include <set>
     3 #include <cmath>
     4 #include <queue>
     5 #include <stack>
     6 #include <cstdio>
     7 #include <string>
     8 #include <vector>
     9 #include <cstdlib>
    10 #include <cstring>
    11 #include <sstream>
    12 #include <iostream>
    13 #include <algorithm>
    14 #include <functional>
    15 using namespace std;
    16 #define rep(i,a,n) for (int i=a;i<n;i++)
    17 #define per(i,a,n) for (int i=n-1;i>=a;i--)
    18 #define all(x) (x).begin(),(x).end()
    19 #define pb push_back
    20 #define mp make_pair
    21 #define lson l,m,rt<<1  
    22 #define rson m+1,r,rt<<1|1 
    23 typedef long long ll;
    24 typedef vector<int> VI;
    25 typedef pair<int, int> PII;
    26 const ll MOD = 1e9 + 7;
    27 const int INF = 0x3f3f3f3f;
    28 const int MAXN = 2e5 + 7;
    29 // head
    30 
    31 int n;
    32 int s[110], f[110];
    33 int dp[MAXN];
    34 
    35 int main() {
    36     int n;
    37     cin >> n;
    38     rep(i, 1, n + 1) cin >> s[i] >> f[i];
    39     rep(i, 0, MAXN) dp[i] = -INF;
    40     dp[100000] = 0;
    41     rep(i, 1, n + 1) {
    42         if (s[i] < 0 && f[i] < 0) continue;
    43         if (s[i] > 0) {
    44             per(j, s[i], 200001) if (dp[j - s[i]] > -INF)
    45                 dp[j] = max(dp[j], dp[j - s[i]] + f[i]);
    46         }
    47         else {
    48             rep(j, s[i], s[i] + 200001) if (dp[j - s[i]] > -INF)
    49                 dp[j] = max(dp[j], dp[j - s[i]] + f[i]);
    50         }
    51     }
    52     int ans = 0;
    53     rep(i, 100000, 200001) if (dp[i] >= 0)
    54         ans = max(ans, dp[i] + i - 100000);
    55     cout << ans << endl;
    56     return 0;
    57 }
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  • 原文地址:https://www.cnblogs.com/baocong/p/6728291.html
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