1.输入一个字符串，从中计算有几个整数
info = input('》》》》') for i in info: if i.isalpha(): info = info.replace(i,' ') l = info.split() print(l) print(len(l))
# a = []
# j = -1
# b = 0
# k = 0
# c = []
# cont = 0
# content = input('请随便输入点东西，最好有数字')
# for i in content:
# j = j + 1
# if i.isdigit():
# a.append(j)
# b = len(a)
# while k <= b-2:
# if a[k+1] != a[k] + 1:
# cont = cont + 1
# print(k)
# k += 1
# cont = cont + 1
# print(a)
# print(cont)
2.作业
# li = ['alex','wusir','eric','rain','alex'] # length = len(li) # print('1长度是'+str(length)) # li.append('seven') # print('2新列表是' + str(li)) # li.insert(0,'Tony') # print(li) # li[1] = 'kelly' # print(li) # l2 = [1,'a',3,4,'hert'] # li.extend(l2) # print(li) # li.extend('qwert') # print(li) # li.remove('eric') # print(li) # li.pop(1) # # # li.reverse() # print(li) # num = li.count('alex') # print(num) # li = [1,3,2,'a',4,'b',5,'c'] # l1 = li[0:3] # print(l1) # l2 = li[3:6] # print(l2) # l3 = li[0:-1:2] # print(l3) # l4 = li[1:-2:2] # print(l4) # l5 = list(li[-1]) # print(l5,type(l5)) # l6 = li[-3:0:-2] # print(l6) #3 lis = [2,3,'k',['qwe',20,['k1',['tt',3,1]],89],'ab','adv'] # lis[3][2][1][0] = lis[3][2][1][0].upper() # print(lis) # lis[3][2][1][0] = lis[3][2][1][0].replace('tt','TT') # print(lis) lis[1] = '100' lis[3][2][1][1] = '100' print(lis)
3.字典的增删改查
增加： 直接用键值加，用dic.setdefault('key','value')
dic1 = {'age' : 18, 'name' : 'jin', 'sex' : 'male'}
# # #增:
# dic1['height'] = 185 #没有键值对，添加
# print(dic1)
# dic1['age'] = 16 #有键值对，则值覆盖
# print(dic1)
# dic1.setdefault('weight')
# dic1.setdefault('weight',150) #没有键值对，增加
# print(dic1)
# dic1.setdefault('name','二哥') #有键值对，不做改变
删除： dic.pop('name','none'),dic.popitem(),dic.clear(),del
#删除 pop 按键删除，有返回值 # print(dic1.pop('age')) # print(dic1) # dic1.pop('ed',None) #不知道有没有错的情况下，删除，可设置返回值 # print(dic1.pop('edd','没有此键')) # dic1 = {'age' : 18, 'name' : 'jin', 'sex' : 'male'} # print(dic1.popitem()) #随机删除,3.6删除最后一个，返回删除的键值 # print(dic1)
# dic1.clear() #清空
# print(dic1)
# del dic1
# print(dic1)
改：dic.update(dic2) 用键值当索引来改
#改 # dic = {'name':'jin','age':18,'sex':'male'} # dic2 = {'name':'alex','weight':75} # dic2.update(dic) #把dic的所有键值对更新到dic2中，没有的加入，有的覆盖 # print(dic) # print(dic2)
查：用for循环来遍历，字典的dic1.keys(),dic1.values(),dic1.items()--->变成了由(key,value)元组的列表
dic1.get('key','Information') 查询键值key,查询到则返回value值，没有查询到相应的key则返回信息Information
dic1 = {'age':18,'name':'jin','sex':'male'}
# print(dic1.keys(),type(dic1.keys())) #就是一个列表，得出键值的列表
# print(dic1.values()) #value值的列表
# print(dic1.items()) #dict_items([('age', 18), ('name', 'jin'), ('sex', 'male')])列表里面是元组，元组里面是键值
# for i in dic1: #键
# print(i)
# for i in dic1.keys():
# print(i)
# for i in dic1.values():
# print(i)
print(dic1.items())
for k,v in dic1.items():
print(k,v)
# ('age', 18)
# ('name', 'jin')
# ('sex', 'male')
# age 18
# name jin
# sex male
#get
v1 = dic1['name']
print(v1)
#没有相应的键就会报错
print(dic1.get('name1','没有这个键'))
4.字典的嵌套
dic = { 'name':['alex','wusir','taibai'], 'python':{ 'time':'121314', 'money':'free', 'address':'CBD', }, 'age':21 } dic['age'] = 56 print(dic) dic['name'].append('xddd') print(dic) dic['name'][1] = dic['name'][1].upper() print(dic) dic['python']['female'] = 6 print(dic) dic['python'].setdefault('male',15) print(dic)