设置是否广告问题

问题：

Input
The input consists of n cases, and the first line consists of one positive integer giving n. The next n lines each contain 3 integers, r, e and c. The first, r, is the expected revenue if you do not advertise, the second, e, is the expected revenue if you do advertise, and the third, c, is the cost of advertising. You can assume that the input will follow these restrictions: -106 ≤ r, e ≤ 106 and 0 ≤ c ≤ 106. 

Output
Output one line for each test case: “advertise”, “do not advertise” or “does not matter”, presenting whether it is most profitable to advertise or not, or whether it does not make any difference. 

Sample Input
3
0 100 70
100 130 30
-100 -70 40

Sample Output
advertise
does not matter
do not advertise

回答：

#include<iostream>  
using namespace std;  
int main()  
{  
    int t,r,e,c;  
    while(scanf("%d",&t)!=EOF)  
    {  
        while(t--)  
        {  
            scanf("%d%d%d",&r,&e,&c);  
            if(r>(e-c))printf("do not advertise ");  
            else if(r<(e-c))printf("advertise ");  
            else printf("does not matter ");  
        }  
 
    }  
    return 0;  
}