Given an unsorted array of integers, find the length of longest continuous
increasing subsequence.
Example 1:
Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.
Example 2:
Input: [2,2,2,2,2] Output: 1 Explanation: The longest continuous increasing subsequence is [2], its length is 1.
Note: Length of the array will not exceed 10,000.
class Solution(object): def findLengthOfLCIS(self, nums): """ :type nums: List[int] :rtype: int """ temp = 1 result = 1 if len(nums)==0: return 0 for i in range(1,len(nums),1): if nums[i]>nums[i-1]: temp +=1 else: temp = 1 result = max(result,temp) return result