zoukankan      html  css  js  c++  java
  • 674. Longest Continuous Increasing Subsequence

    Given an unsorted array of integers, find the length of longest continuous increasing subsequence.

    Example 1:

    Input: [1,3,5,4,7]
    Output: 3
    Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. 
    Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4. 
    

    Example 2:

    Input: [2,2,2,2,2]
    Output: 1
    Explanation: The longest continuous increasing subsequence is [2], its length is 1. 
    

    Note: Length of the array will not exceed 10,000.

    class Solution(object):
        def findLengthOfLCIS(self, nums):
            """
            :type nums: List[int]
            :rtype: int
            """
            temp = 1
            result = 1
            if len(nums)==0:
                return 0
            for i in range(1,len(nums),1):
                if nums[i]>nums[i-1]:
                    temp +=1
                else:
                    temp = 1
                result = max(result,temp)
            return result
  • 相关阅读:
    arthas-常用命令
    k8s-容器技术-Mount Namespace
    k8s-statefulset介绍
    k8s-yaml配置文件
    k8s-控制器模式
    k8s-pod使用
    k8s-pod简介(半原创)
    k8s-安装我们第一个集群
    k8s-安装
    Corn表达式详解(转)
  • 原文地址:https://www.cnblogs.com/bernieloveslife/p/7692663.html
Copyright © 2011-2022 走看看