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  • LuoguP3128 [USACO15DEC]最大流Max Flow (树上差分)

    跟LOJ10131暗的连锁 相似,只是对于(lca)节点把它和父亲减一

    #include <cstdio>
    #include <iostream>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    #define R(a,b,c) for(register int a = (b); (a) <= (c); ++(a))
    #define nR(a,b,c) for(register int a = (b); (a) >= (c); --(a))
    #define Fill(a,b) memset(a, b, sizeof(a))
    #define Max(a,b) ((a) > (b) ? (a) : (b))
    #define Min(a,b) ((a) < (b) ? (a) : (b))
    #define Swap(a,b) ((a) ^= (b) ^= (a) ^= (b))
    #define ll long long
    #define u32 unsigned int
    #define u64 unsigned long long
    
    #define ON_DEBUGG
    
    #ifdef ON_DEBUGG
    
    #define D_e_Line printf("
    ----------
    ") 
    #define D_e(x) cout << (#x) << " : " << x << endl
    #define Pause() system("pause")
    #define FileOpen() freopen("in.txt", "r", stdin)
    #define FileSave() freopen("out.txt", "w", stdout)
    #include <ctime>
    #define TIME() fprintf(stderr, "
    time: %.3fms
    ", clock() * 1000.0 / CLOCKS_PER_SEC);
    
    #else
    
    #define D_e_Line ;
    #define D_e(x) ;
    #define Pause() ;
    #define FileOpen() ;
    #define FileSave() ;
    #define TIME() ;
    //char buf[1 << 21], *p1 = buf, *p2 = buf;
    //#define getchar() (p1 == p2 && (p2 = (p1 = buf) + fread(buf, 1, 1 << 21, stdin), p1 == p2) ? EOF : *p1++)
    
    #endif
    
    using namespace std;
    struct ios{
    	template<typename ATP>inline ios& operator >> (ATP &x){
    		x = 0; int f = 1; char ch;
    		for(ch = getchar(); ch < '0' || ch > '9'; ch = getchar()) if(ch == '-') f = -1;
    		while(ch >= '0' && ch <= '9') x = x * 10 + (ch ^ '0'), ch = getchar();
    		x *= f;
    		return *this;
    	}
    }io;
    
    template<typename ATP>inline ATP max(ATP &a, ATP &b){
    	return a > b ? a : b;
    }
    template<typename ATP>inline ATP min(ATP &a, ATP &b){
    	return a < b ? a : b;
    }
    template<typename ATP>inline ATP abs(ATP &a){
    	return a < 0 ? -a : a;
    }
    
    
    const int N = 500007;
    
    struct Edge{
    	int nxt, pre;
    }e[N << 1];
    int head[N], cntEdge;
    inline void add(int u, int v){
    	e[++cntEdge] = (Edge){ head[u], v}, head[u] = cntEdge;
    }
    
    int siz[N], son[N], fa[N], dep[N], top[N];
    inline void DFS_First(int u, int father){
    	dep[u] = dep[father] + 1, fa[u] = father, siz[u] = 1;
    	for(register int i = head[u]; i; i = e[i].nxt){
    		int v = e[i].pre;
    		if(v == father) continue;
    		DFS_First(v, u);
    		siz[u] += siz[v];
    		if(!son[u] || siz[v] > siz[son[u]]) son[u] = v;
    	}
    }
    inline void DFS_Second(int u, int TP){
    	top[u] = TP;
    	if(!son[u]) return;
    	DFS_Second(son[u], TP);
    	for(register int i = head[u]; i; i = e[i].nxt){
    		int v = e[i].pre;
    		if(v != fa[u] && v != son[u])
    			DFS_Second(v, v);
    	}
    }
    inline int LCA(int x, int y){
    	while(top[x] != top[y]){
    		if(dep[top[x]] < dep[top[y]]) Swap(x, y);
    		x = fa[top[x]];
    	}
    	return dep[x] < dep[y] ? x : y;
    }
    
    int n, m;
    long long ans, sum[N];
    inline void DFS_Ans(int u){
    	for(register int i = head[u]; i; i = e[i].nxt){
    		int v = e[i].pre;
    		if(v == fa[u]) continue;
    		DFS_Ans(v);
    		sum[u] += sum[v];
    		ans = max(ans, sum[v]);
    	}
    }
    int main(){
    //FileOpen();
    
    	io >> n >> m;
    	R(i,2,n){
    		int u, v;
    		io >> u >> v;
    		add(u, v);
    		add(v, u);
    	}
    	
    	DFS_First(1, 0);
    	DFS_Second(1, 1);
    	
    	R(i,1,m){
    		int u, v;
    		io >> u >> v;
    		int lca = LCA(u, v);
    		++sum[u], ++sum[v];
    		--sum[lca], --sum[fa[lca]];
    	}
    	
    	DFS_Ans(1);
    	
    	printf("%lld
    ", ans);
    	
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/bingoyes/p/11496309.html
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