C. Table Decorations（Codeforces Round 273)

C. Table Decorations

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

You have r red, g green and b blue balloons. To decorate a single table for the banquet you need exactly three balloons. Three balloons attached to some table shouldn't have the same color. What maximum number t of tables can be decorated if we know number of balloons of each color?

Your task is to write a program that for given values r, g and b will find the maximum number t of tables, that can be decorated in the required manner.

Input

The single line contains three integers r, g and b (0 ≤ r, g, b ≤ 2·109) — the number of red, green and blue baloons respectively. The numbers are separated by exactly one space.

Output

Print a single integer t — the maximum number of tables that can be decorated in the required manner.

Sample test(s)

input

5 4 3

output

4

input

1 1 1

output

1

input

2 3 3

output

2

Note

In the first sample you can decorate the tables with the following balloon sets: "rgg", "gbb", "brr", "rrg", where "r", "g" and "b" represent the red, green and blue balls, respectively.

首先要明确，当最大的气球数量的一半小于另外两种颜色的数量之和，肯定能够组成所有颜色数量之和/3,当最大的

气球数量的一半大于等于另外两种颜色的数量之和，所有组成为2+1，2为最多数量的颜色。

代码：

#include <iostream>
#include <cstdio>
#include <cstdio>
#include <algorithm>
using namespace std;

int main()
{
    long long a[3];
    scanf("%I64d%I64d%I64d",&a[0],&a[1],&a[2]);
    sort(a,a+3);
    long long ans=0;
    if((a[0]+a[1])<=a[2]/2)
    {
       ans=a[0]+a[1];
    }
    else
    {
        ans=(a[0]+a[1]+a[2])/3;
    }
    printf("%I64d
",ans);
    return 0;
}