Given a binary array, find the maximum number of consecutive 1s in this array.
Example 1:
Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.
Note:
- The input array will only contain
0
and1
. - The length of input array is a positive integer and will not exceed 10,000
class Solution: def findMaxConsecutiveOnes(self, nums: List[int]) -> int: max1 = 0 tmp = 0 for i in nums: if i == 1: tmp += 1 else: max1 = max(max1,tmp) tmp = 0 max1 = max(max1,tmp) return max1