Given an integer array nums
, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.
Example:
Input: [-2,1,-3,4,-1,2,1,-5,4]
,
Output: 6
Explanation: [4,-1,2,1]
has the largest sum = 6
.
Follow up:
If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
贪心:
class Solution(object): def maxSubArray(self, nums): """ :type nums: List[int] :rtype: int """ ans = s = nums[0] for i in xrange(1, len(nums)): if s > 0: s = nums[i]+s else: s = nums[i] ans = max(s, ans) return ans
DP解法://dp[i] means the maximum subarray ending with A[i];
class Solution(object): def maxSubArray(self, nums): """ :type nums: List[int] :rtype: int """ dp = [0]*len(nums) ans = dp[0] = nums[0] for i in xrange(1, len(nums)): dp[i] = max(dp[i-1]+nums[i], nums[i]) ans = max(ans, dp[i]) return ans
递归解法:
TODO