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  • sql server 语句

    1.with as 用法

    1 with temp
    2 as
    3 (
    4 select a.* from [dbo].[erdos_tradepave] a join [dbo].[erdos_checkin] b on a.pk_checkin = b.pk_checkin
    5 where b.isback='N' and b.isexchange ='Y' )
    6 
    7 select * from [dbo].[erdos_tradepave] e where 
    8 [PK_TRADEPAVE] in (select c.[PK_TRADEPAVE] from [dbo].[erdos_tradepave] c left join [dbo].[erdos_checkin] d on c.pk_checkin = d.pk_checkin

    2.with as 多个表

    with temp
    as
    (
    select a.* from [dbo].[erdos_tradepave] a join [dbo].[erdos_checkin] b on a.pk_checkin = b.pk_checkin
    where b.isback='N' and b.isexchange ='Y' ),
    
    temp1
    as
    (
    select * from [dbo].[erdos_tradepave] e where 
    [PK_TRADEPAVE] in (select c.[PK_TRADEPAVE] from [dbo].[erdos_tradepave] c left join [dbo].[erdos_checkin] d on c.pk_checkin = d.pk_checkin)
    
    select * from temp1

    3.将一个表的信息插入新表

    insert into [Accommodation].[dbo].[CheckIn]([Cid],[OrderCode],[Name],[Sex],[IdCard],[PhoneNo],[FeeScaleCid],[Fee],[RoomCid],[CheckInDateTime])select a.[Cid],a.[VBILLNO],a.[NAME],1,a.[ID],isnull(a.[CONTACTTYPE],''),b.[Cid],b.[FeeValue],c.[Cid],a.[INDATE] from
    [Erdos].[dbo].[erdos_checkin] a left join [Accommodation].[dbo].[FeeScale] b on b.[FeeValue]=a.[ACCOMMODATIONCOST] left join [Erdos].[dbo].[erdos_dormdoc] c on c.[PK_DORMDOC]=a.[PK_DORMDOC] where a.[DR]=0 and b.[FeeType]=1 and a.[NAME] is not null;

    4.update与join联合使用

    update a set a.[Sex]=0 from [Accommodation].[dbo].[CheckIn] a left join [Erdos].[dbo].[erdos_checkin] b on b.Cid=a.Cid where b.[SEX]=1;

    5.判断数据库表中是否包含某些字符,用charindex判断

    update a set a.DormCategoryCid=ISNULL(c.Cid,'D4CD56C7-E861-4EA4-886F-E4ED47BC73BF')
    from [Erdos].[dbo].[erdos_dormclass] a left join [Erdos].[dbo].[erdos_dormclass] b on b.PK_DORMCLASS=a.PK_DORMCLASSF left join [Accommodation].[dbo].[DormCategory] c on CHARINDEX(c.CategoryName,b.DORMCLASSNAME)>0  where CHARINDEX('专家',a.DORMCLASSNAME)=0 and CHARINDEX('女生',a.DORMCLASSNAME)=0 and CHARINDEX('男生',a.DORMCLASSNAME)=0 and a.ILEVEL=3 and a.DR=0;

    charindex(要查是否包含的内容,字段名):=0表示不包含,>0表示包含

    6.case when 用法

    insert  into Accommodation.dbo.Change(Cid,checkincid,fee,PhoneNo,Reason,IdCard,GroupCid,IsCash,CashEndTime,Name
    ,CorpCid,DepartmentCid,RoomCid,Post,ChangeDateTime,Sex,groupname,corpname,department,[status])
    select NEWID(),b.cid,a.accommodationcost,a.contacttype,a.hpreason,a.id,a.industrial_group,case  a.ISXJFLAG when  'Y' then 1 else 0 end ,a.jfenddate,a.NAME
    ,a.pk_corp,a.pk_deptdoc,c.cid,a.pk_om_job,a.TPDATE,a.SEX,d.CHARGEDEPTNAME,d.UNITNAME,e.deptname,a.[Status]
     from dbo.erdos_tradepave a left join dbo.erdos_checkin b on 
    a.pk_tradepave=b.pk_tradepave left join dbo.erdos_dormdoc c on a.pk_dormdocnew=c.PK_DORMDOC
    left join dbo.bd_corp d on a.pk_corp = d.pk_corp 
    left join [dbo].[bd_deptdoc] e on a.pk_deptdoc=e.pk_deptdoc
     where a.DR=0  
     and b.Cid is not null and a.NAME is not null ;

    case+字段名+when+判断值+then 相等改变成的值 else 不等时改变成的值

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  • 原文地址:https://www.cnblogs.com/bosamvs/p/6479628.html
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