zoukankan      html  css  js  c++  java
  • 2017 JUST Programming Contest 3.0 K. Malek and Summer Semester

    K. Malek and Summer Semester
    time limit per test
    1.0 s
    memory limit per test
    256 MB
    input
    standard input
    output
    standard output

    Malek registered n courses for the summer semester. Malek has a success rate m, which means he has to succeed at least in ceil(n × m)courses out of the n courses, in order to consider the summer semester as a successful semester. Malek is considered successful in the ithcourse, if his grade on this course was greater than or equal to 50.

    ceil(x) is the smallest integer greater than or equal to x. For example, ceil(0.95) = 1ceil(4) = 4, and ceil(7.001) = 8.

    Malek will give you his grades in the n courses, and your task is to tell him whether the summer semester was a successful semester or not.

    Input

    The first line contains an integer T (1 ≤ T ≤ 100), where T is the number of test cases.

    The first line of each test case contains an integer n and a real number m (1 ≤ n ≤ 100) (0 < m < 1), where n is the number of courses, and m is the required success rate.

    The second line contains n integers a1, a2, ..., an (0 ≤ ai ≤ 100), where ai is the grade of the ith course.

    The success rate m is given with exactly two digits after the decimal point.

    Output

    For each test case, print a single line containing "YES" (without quotes), if the summer semester was a successful semester for Malek. Otherwise, print "NO" (without quotes).

    Example
    input
    2
    5 0.60
    45 46 48 48 50
    5 0.75
    100 99 98 97 100
    
    output
    NO
    YES
    


    #include<iostream>
    #include<cstdio>
    #include<cmath>
    using namespace std;
    #define ll long long
    const int maxn=100005;
    int a[105];
    int main()
    {
    //    freopen("in.txt","r",stdin);
        int T,n;
        double m;
        scanf("%d",&T);
        while(T--)
        {
            scanf("%d%lf",&n,&m);
            double guo=n*m;
            int guo1=ceil(guo);
            for(int i=0;i<n;i++)
                scanf("%d",&a[i]);
            int ans=0;
            for(int i=0;i<n;i++)
            {
                if(a[i]>=50)
                    ans++;
            }
            if(ans>=guo1)
                cout<<"YES"<<endl;
            else
                cout<<"NO"<<endl;
        }
    }



  • 相关阅读:
    关于Mac上的开发工具
    关于VS2008和VS2013中字体的选择
    实验四 使用ASP.NET内置对象 总结
    实验三 使用ASP.NET常用服务器控件 总结
    实验二 C#程序设计 总结
    实验一 ASP.NET应用环境配置 总结
    关于PHP.INI中的错误ERROR报告级别设置
    获取当前网址跟目录
    PHP获取站点根目录
    php 上传图片
  • 原文地址:https://www.cnblogs.com/bryce1010/p/9387155.html
Copyright © 2011-2022 走看看