我们有两个字符串 20130728 和 20130803 如何利用计算相差的天数呢
time1=time.strptime("20130803","%Y%m%d")
time2=time.strptime("20130728","%Y%m%d")
time1和time2 如下 结构
time.struct_time(tm_year=2013, tm_mon=8, tm_mday=03, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=4, tm_yday=242, tm_isdst=-1)
于是乎，diffday=365*(time1.tm_year-time2.tm_year) + time.tm_mday-time2.tm_mday