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  • Jam's problem again cdq分治

      题意:  问每个点的等级

    CDQ 注意处理一下完全相等的点即可

    #include<bits/stdc++.h>
    using namespace std;
    //input by bxd
    #define rep(i,a,b) for(int i=(a);i<=(b);i++)
    #define repp(i,a,b) for(int i=(a);i>=(b);--i)
    #define RI(n) scanf("%d",&(n))
    #define RII(n,m) scanf("%d%d",&n,&m)
    #define RIII(n,m,k) scanf("%d%d%d",&n,&m,&k)
    #define RS(s) scanf("%s",s);
    #define ll long long
    #define see(x) (cerr<<(#x)<<'='<<(x)<<endl)
    #define pb push_back
    #define inf 0x3f3f3f3f
    #define CLR(A,v)  memset(A,v,sizeof A)
    #define lson l,m,pos<<1
    #define rson m+1,r,pos<<1|1
    typedef pair<int,int>pii;
    //////////////////////////////////
    const int N=1e6+10;
    int M,t[N],n,cnt,num,ans[N],maxx;
    int lowbit(int i){return i&(-i);}
    void add(int x,int v){for(;x<=100000+5;x+=lowbit(x))t[x]+=v;}
    int get(int x){int ans=0;for(;x;x-=lowbit(x)) ans+=t[x];return ans;}
    
    struct node
    {
        int x,y,z,w,ans,id;
    }s[N];
    bool cmp(node a,node b)
    {
        return a.x==b.x?a.y==b.y?a.z<b.z:a.y<b.y:a.x<b.x;
    }
    bool cmpy(node a,node b)
    {
        return a.y<b.y||a.y==b.y&&a.z<b.z;
    }
    void cbq(int l,int r)
    {
        if(l==r)return ;
        int mid=(l+r)>>1;
        cbq(l,mid);cbq(mid+1,r);
        sort(s+l,s+mid+1,cmpy);sort(s+mid+1,s+r+1,cmpy);
        int j=l;
        rep(i,mid+1,r)
        {
            while(s[j].y<=s[i].y&&j<=mid)
            add(s[j].z,1),j++;
            ans[s[i].id]+=get(s[i].z);
        }
        rep(i,l,j-1)//这里j-1 不能改成mid
        add(s[i].z,-1);
    }
    
    void sol()
    {
        RI(n);//CLR(t,0);
    
        rep(i,1,n){RIII(s[i].x,s[i].y,s[i].z);s[i].id=i;ans[i]=0;  }
        sort(s+1,s+1+n,cmp);
    
        cbq(1,n);
    
        repp(i,n-1,1)
        if(s[i].x==s[i+1].x&&s[i].y==s[i+1].y&&s[i].z==s[i+1].z)
        ans[s[i].id]=ans[s[i+1].id];
    
        rep(i,1,n)
        printf("%d
    ",ans[i]);
    }
    
    int main()
    {
        int cas;RI(cas);
        while(cas--)sol();
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/bxd123/p/11213849.html
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