推算身份证的生日位

#5321251987****1171
# 获取日期列表，从01到31
# t代表身份证号码的位数，w表示每一位的加权因子
t = []
w = []
for i in range(0, 18):
    t1 = i + 1
    t.append(t1)
    w1 = (2 ** (t1 - 1)) % 11
    w.append(w1)
# 队列w要做一个反序
w = w[::-1]


# 根据前17位的余数，计算第18位校验位的值
def for_check(n):
    # t = 0
    for i in range(0, 12):
        if (n + i) % 11 == 1:
            t = i % 11
    if t == 10:
        t = 'X'
    return t


# 根据身份证的前17位，求和取余，返回余数
def for_mod(id):
    sum = 0
    for i in range(0, 17):
        sum += int(id[i]) * int(w[i])
        # print(int(id[i]),int(w[i]),sum)
    sum = sum % 11
    # print(sum)
    return sum


# 验证身份证有效性
def check_true(id):
    # print(for_check(for_mod(id[:-1])))
    if id[-1] == 'X':
        if for_check(for_mod(id[:-1])) == 'X':
            return True
        else:
            return False
    else:
        if for_check(for_mod(id[:-1])) == int(id[-1]):
            return True
        else:
            return False

day = []
for i in range(0,4):
    for j in range(0,10):
        d = str(i) + str(j)
        day.append(d)
        if d == '31':
            break
    if d == '31':
        break
day = day[1:]

# 获取月份列表，从01到12
month = []
for i in range(0,3):
    for j in range(0,10):
        d = str(i) + str(j)
        month.append(d)
        if d == '12':
            break
    if d == '12':
        break
month = month[1:]

# 获取年月列表，从0101到1231，剔除不存在的日期
mmdd = []
for i in month:
    for j in day:
        md = i + j
        mmdd.append(md)
mmdd.remove('0230')
mmdd.remove('0231')
mmdd.remove('0431')
mmdd.remove('0631')
mmdd.remove('0931')
mmdd.remove('1131')

#以下代码用于遍历所有日期，打印出通过校验的身份证号码
id1 = '5321251987'
id3 = '1171'
j = 0
for i in mmdd:
    theid = id1 + i + id3
    if check_true(theid):
        print(theid)
        j += 1