（补题 水题 汇总）四川大学第二届SCUACM新生赛

B-丁姐姐喜欢LCS

原题链接

输入

abc
bca
wad
ad
as
asd
wa
aw
wa
wwa  

输出

bc
ad
as
a

解题思路

暴力呀！暴力呀！暴力呀！！！（我真是白学了ORZ）

代码样例

#include <bits/stdc++.h>
using namespace std;

int main(){
    string a,b;
    while(cin >> a >> b){
        bool judge = false;
        int cnt=0;
        for(int i=0; i < a.length(); i++){
            if(judge){
                if (a[i] != b[cnt])
                    judge = false;
            }
            if(a[i] == b[cnt]){
                judge = true;
                cnt++;
            }
        }
        if(judge)
            for(int i=0;i < cnt; i++)
                cout << b[i];
        else
            cout << ""NULL!"";
        cout << endl;
    }
    return 0;
}

J-n=abc

原题链接

输入

2
10
12

输出

No solution
12=2*2*3

解题思路

暴力呀！！！暴力呀！！！暴力呀！！！（我真是白学了ORZ ORZ）

代码样例

#include <bits/stdc++.h>
using namespace std;
 
int main()
{
    int t;
    cin >> t;
    while (t--)
    {
        int n;
        cin >> n;
        int a,b,c;
        for(int i = 2; i < n; i++)
            if(n % i == 0)
            {
                int m = n / i;
                for(int j = i; j <= m / j + 1; j++)
     
                    if(m % j == 0 && j <= m / j)
                        if(m/j - i < cmp)
                            a = i, b = j, c = m/j, cmp = m/j - i;
            }
        if (judge == n)
            cout << "No solution" << endl;
        else
            cout << n << "=" << a << "*" << b << "*" << c << endl;
    }
    return 0;
}

L-双流机场

原题链接

输入

2
3 3
010
010
3 3
011
011

输出

Sad
Happy

解题思路

水题，只需要判断四个角是否能够有出路和入路即可

代码样例

#include <bits/stdc++.h>
using namespace std;

int main(){
    int t;
    cin >> t;
    while(t--){
        int n,m;
        cin >> n >> m;
        string a,b;
        cin >> a >> b;
        bool judge=false;
        if(a[0] == '0'&&b[m-1] == '0')
            judge = true;
        if(a[0] == '1'&&b[0] == '0')
            judge = true;
        if(a[n-1] == '0'&&b[m-1] == '1')
            judge = true;
        if(a[n-1] == '1'&&b[0] == '1')
            judge = true;
        if(judge)
            cout << "Sad" << endl;
        else
            cout << "Happy" << endl;
    }
    return 0;
}

我知道了，我收拾收拾马上滚ORZ