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  • 面试题(一)

         题1:给定一个字符串、一个起始字符和一个终止字符,找起始字符和终止字符之间的字符串。

    public static void main(String[] args) {
    		String str = "abcdcbaabcdfasdfbadbcbdaaosjfabcs";
    		String firstChar = "b";
    		String lastChar = "c";
    		int firstCharIndex = str.indexOf(firstChar);
    		int lastCharIndex = str.lastIndexOf(lastChar);
    		int number = 0;
    		while (firstCharIndex > -1 && firstCharIndex < str.length()
    				&& firstCharIndex < lastCharIndex) {
    			while (firstCharIndex > -1 && firstCharIndex < lastCharIndex
    					&& lastCharIndex > -1) {
    				String subStr = str
    						.substring(firstCharIndex, lastCharIndex + 1);
    				System.out.println("第" + number++ + "个字符串为:" + subStr
    						+ ";起始位置为:" + firstCharIndex + ",终止位置为:"
    						+ lastCharIndex);
    				lastCharIndex = str.lastIndexOf(lastChar, lastCharIndex - 1);
    			}
    			lastCharIndex = str.lastIndexOf(lastChar);
    			firstCharIndex = str.indexOf(firstChar, firstCharIndex + 1);
    		}
    
    	}
    

      

    题2:经典面试题,将数字转化为人民币大写

    /**
         * 转化
         * @param oInt
         * @return
         */
        public static String strToChinese(int oInt){
            String[] s3 = {"","万","亿","兆"};
            int i = 0;
            String s = "";
            while(oInt>0){
                int fourBit = oInt%10000;
                String temp = handleFourNumberInt(fourBit);
                if(s==""||(s.length()>1&&s.charAt(1)=='千')){
                    s = temp+s3[i]+s;
                }else{
                    s = temp+s3[i]+"零"+s;
                }
                oInt = oInt/10000;
                i++;
            }
            System.out.println("S:"+s);
            return s;
        }
        /**
         * 处理四位以下下整数
         * @param oInt
         * @return
         */
        public static String handleFourNumberInt(int oInt){
            String[] s1 = {"零","一","二","三","四","五","六","七","八","九"};
            String[] s2 = {"","十","百","千"};
            String resultStr = "";
            int i=0;
            while(oInt>9){
                int l = oInt%10;
                if(l==0){//如果resultStr为空,不添加
                    int size = resultStr.length();
                    if(size==0){
                        ;
                    }else if(resultStr.charAt(0)=='零'){  //如果前面已有零,不添加
                        ;
                    }else{
                        resultStr = "零"+resultStr;
                    }
                }else{
                    resultStr = s1[l]+s2[i]+resultStr;
                }
                oInt = oInt/10;
                i++;
            }
            resultStr = s1[oInt]+s2[i]+resultStr;
            System.out.println(resultStr);
            return resultStr;
        }
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  • 原文地址:https://www.cnblogs.com/caijing/p/3344624.html
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