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  • es6 filter() 数组过滤方法总结

     

    1.创建一个数组,判断数组中是否存在某个值

    var newarr = [
      { num: 1, val: 'ceshi', flag: 'aa' },
      { num: 2, val: 'ceshi2', flag: 'aa2'  }
    ]
    console.log(newarr.filter(item => item.num===2 ))

    2.也可以通过上面方法过滤掉num为2的留下num为1的

    var newarr = [
      { num: 1, val: 'ceshi', flag: 'aa' },
      { num: 2, val: 'ceshi2', flag: 'aa2'  }
    ]
    console.log(newarr.filter(item => item.num!=2 ))

    3.去掉空数组空字符串、undefined、null

    var arr = ['1','2',undefined, '3.jpg',undefined]
    var newArr = arr.filter(item => item)
    console.log(newArr)
    
    var arr = ['1','2',null, '3.jpg',null]
    var newArr = arr.filter(item => item)
    console.log(newArr)
    
    >//空字符串里面不能包含空格
    var arr = ['1','2','', '3.jpg','']
    var newArr = arr.filter(item => item)
    console.log(newArr)

    4.去掉数组中不符合项

    var arr = [20,30,50, 96,50]
    var newArr = arr.filter(item => item>40)  
    console.log(newArr)

    5.过滤不符合项

    var arr = ['10','12','23','44','42']
    var newArr = arr.filter(item => item.indexOf('2')<0) 
    console.log(newArr)

    6.数组去重

    var arr = [1, 2, 2, 3, 4, 5, 5, 6, 7, 7,8,8,0,8,6,3,4,56,2];
    var arr2 = arr.filter((x, index,self)=>self.indexOf(x)===index)  
    console.log(arr2); //[1, 2, 3, 4, 5, 6, 7, 8, 0, 56]
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  • 原文地址:https://www.cnblogs.com/catherLee/p/10457043.html
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