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  • 最大连续子数组和(最大字段和)

    最大连续子数组:

    问题:

    给定n个整数(可能为负数)组成的序列a[1],a[2],a[3],…,a[n],求该序列如a[i]+a[i+1]+…+a[j]的子段和的最大值。当所给的整数均为负数时定义子段和为0,依此定义,所求的最优值为: Max{0,a[i]+a[i+1]+…+a[j]},1<=i<=j<=n

    例如,当(a[1],a[2],a[3],a[4],a[5],a[6])=(-2,11,-4,13,-5,-2)时,最大子段和为20。
    分治法:
    def Max_cross_sum(list1,left,mid,right):
        left_sum = 0
        right_sum = 0
        temp = 0
        mid_1 = mid
        while mid_1>=left:
            temp += list1[mid_1]
            left_sum = max(left_sum,temp)
            mid_1 -= 1
        temp = 0
        mid_1 = mid + 1
        while mid_1<=right:
            temp += list1[mid_1]
            right_sum = max(right_sum,temp)
            mid_1 += 1
        return left_sum+right_sum
    def Max_sum(list1,left,right):
        if left == right:
            return list1[left]
        mid = (left+right)//2
        left_sum = Max_sum(list1,left,mid)
        right_sum = Max_sum(list1,mid+1,right)
        cross_sum = Max_cross_sum(list1,left,mid,right)
        return max(left_sum,max(right_sum,cross_sum))    
    list1 = [-2,1,-3,4,-10,2,10,-5,6]
    Max_sum(list1,0,len(list1)-1)
    
    动态规划法:
    def Max_sum(lis1):
        temp = 0
        max_sum = 0
        for cnt in list1:
            temp = max(temp+cnt,cnt)
            max_sum = max(max_sum,temp)
        return max_sum
    list1 = [-2,1,-3,4,-1,2,10,-5,1]
    Max_sum(list1)
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  • 原文地址:https://www.cnblogs.com/cccf/p/12651718.html
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