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  • 第一章 线性表

       3. 结点类的描述:

     1 //结点类的描述
     2 public class Node{
     3 
     4     public Object data;
     5     public Node next;
     6     
     7     public Node(){
     8         this(null, null);
     9     }
    10     public Node(Object data){
    11         this(data, null);
    12     }
    13     public Node(Object data, Node next){
    14         this.data = data;
    15         this.next = next;
    16     }
    17 }
    18 
    19 //单链表的描述
    20 import java.util.Scaner;
    21 public class LinkList implement IList{
    22     
    23     public Node head;
    24     
    25     public LinkList(){
    26         head = new Node();
    27     }
    28     public LinkList(int n, boolean order) throws Exception{
    29         this();
    30         if(order)
    31             creat1(n);
    32         else
    33             creat2(n);
    34     }
    35     public void create1(int n) throws Exception{
    36         ...
    37     }
    38     public void display(){
    39         Node node = head.next;
    40         while(node.next != null){
    41             System.out.print(node.data + ' ');//printIn("单链表的数据是:" + node.data);
    42             node = node.next;
    43         System.out.printIn();
    44     }
    45     public Object get(int i) throws Exception{
    46         Node node = head.next;
    47         int j = 0;
    48         while(j < i && node != null)//(j <= i && node.next == null){
    49             node = node.next;
    50             ++j;
    51         }
    52         if(j > i || node = null)//(j < i || node.next == null)
    53             throw new Exception("第" + i + "个元素不存在");
    54         return node.data;
    55     }
    56     /*public void create1(int n){
    57         Node node = head;
    58         while(j < n){
    59             node.next = node;
    60         }
    61     }
    62     */
    63     
    64 }
    View Code

       2. 顺序表前驱:-- NOT BUG FREE

     1 public class Example2{
     2     public static void main(String[] args) throws Exception{
     3         int n = 10;
     4         SqList F = new SqList(80);
     5         for (int j = 0; j < 81; j++)
     6             F.insert(j, j);
     7         System.out.printIn{"请输入要查找的第i个元素前驱值i"};
     8         int i = new Scanner(System.in).nextInt();
     9         if (0 < i && i < 80)
    10             System.out.printIn{i + "的前驱元素是:" + F.get(i - 2)};
    11         else
    12             System.out.printIn{"直接前驱不存在"};
    13     }
    14 }
    View Code

        1. 实现建立顺序表并查找元素,输出其位置:-- NOT BUG FREE

     1 public class Test2{
     2     public static void main(){
     3         int j = 0;
     4         SqList F = new SqList(10);
     5         F.insert(0, 'a');
     6         F.insert(1, 'z');
     7         F.insert(2, 'd');
     8         F.insert(3, 'm');
     9         F.insert(4, 'z');
    10         F.indexOf('z');
    11         if(j != -1)
    12             System.out.printIn("字母'z'的位置为:" + j);
    13         else
    14             System.out.printIn("顺序表中没有'z'");
    15     }
    16 }
    View Code
     1 public class Test2 {
     2 
     3       public static void main(String[] args) throws Exception {
     4 
     5          SqList F = new SqList(10);
     6          F.insert(0, 'a');
     7          F.insert(1, 'z');
     8          F.insert(2, 'd');
     9          F.insert(3, 'm');
    10          F.insert(4, 'z');
    11          int j = F.indexOf('z');
    12          if (j != -1)
    13              System.out.printIn("字母'z'的位置为:" + j);
    14          else
    15             System.out.printIn("顺序表中没有'z'");
    16     }
    17 }
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  • 原文地址:https://www.cnblogs.com/cenmny/p/6531816.html
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