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  • Leetcode202 Happy number

    Description

    Write an algorithm to determine if a number n is "happy".

    A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.

    Return True if n is a happy number, and False if not.

    Input: 19

    Output: true

    Explanation:
    12 + 92 = 82
    82 + 22 = 68
    62 + 82 = 100
    12 + 02 + 02 = 1

    Analysis

    判断环的两大方法

    Hashset

    class Solution {
    public:
        bool isHappy(int n) {
            while(n!=1){
                n=process(n);
                if(a[n]==1)return 0;
                a[n]=1;
            }
            return 1;
        }
    private:
        int process(int x){
            int sum=0;
            while(x!=0){
                int u=x%10;
                sum+=u*u;
                x/=10;
            }
            return sum;
        }
        int a[50000];
    };
    

    龟兔赛跑法


    设定两个指针,一快一慢,快的一次走2步,慢的一次走1步

    Code

    class Solution {
    public:
        bool isHappy(int n) {
            int a=n,b=n;
            while(a!=1){
                a=process(a);
                a=process(a);
                b=process(b);
                if(a==b)break;
            }
            return a==1;
        }
    private:
        int process(int x){
            int sum=0;
            while(x!=0){
                int u=x%10;
                sum+=u*u;
                x/=10;
            }
            return sum;
        }
    };
    
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  • 原文地址:https://www.cnblogs.com/chanceYu/p/12808107.html
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