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  • SPOJ LCS2 后缀自动机

    多串的LCS,注意要利用拓扑序更新suf的len。

    我用min,max,三目会超时,所以都改成了if,else

    #pragma warning(disable:4996)
    #include<cstring>
    #include<string>
    #include<iostream>
    #include<cmath>
    #include<vector>
    #include<algorithm>
    #define maxn 100050
    using namespace std;
    
    struct State{
    	State *suf, *go[26];
    	int val, len[2];
    	State() :suf(0), val(0){
    		memset(go, 0, sizeof(go));
    		memset(len, 0, sizeof(len));
    	}
    }*root, *last;
    
    State statePool[maxn * 2], *cur;
    
    void init()
    {
    	cur = statePool;
    	root = last = cur++;
    }
    
    void extend(int w)
    {
    	State *p = last, *np = cur++;
    	np->val = p->val + 1;
    	np->len[1] = np->val;
    	while (p&&!p->go[w]) p->go[w] = np, p = p->suf;
    	if (!p) np->suf = root;
    	else{
    		State *q = p->go[w];
    		if (p->val + 1 == q->val){
    			np->suf = q;
    		}
    		else{
    			State *nq = cur++;
    			memcpy(nq->go, q->go, sizeof q->go);
    			nq->val = p->val + 1;
    			nq->len[1] = nq->val;
    			nq->suf = q->suf;
    			q->suf = nq;
    			np->suf = nq;
    			while (p&&p->go[w] == q){
    				p->go[w] = nq, p = p->suf;
    			}
    		}
    	}
    	last = np;
    }
    
    char str[maxn];
    int n;
    
    int bcnt[maxn];
    State *b[maxn * 2];
    
    int main()
    {
    	n = 0;
    	scanf("%s", str);
    	init();
    	int len = strlen(str);
    	for (int i = 0; i < len; i++){
    		extend(str[i] - 'a');
    	}
    	int tot = cur - root;
    	memset(bcnt, 0, sizeof(bcnt));
    	for (int i = 0; i < tot; i++) bcnt[statePool[i].val]++;
    	for (int i = 1; i <= len; i++) bcnt[i] += bcnt[i - 1];
    	for (int i = tot - 1; i >= 0; i--) b[--bcnt[statePool[i].val]] = &statePool[i];
    	while (scanf("%s", str) != EOF){
    		int lenb = strlen(str);
    		int cnt = 0;
    		State *p = root;
    		for (int i = 0; i < lenb; i++){
    			if (p->go[str[i] - 'a']){
    				cnt++;
    				p = p->go[str[i] - 'a'];
    			}
    			else{
    				while (p&&!p->go[str[i] - 'a']) p = p->suf;
    				if (!p) {
    					p = root;
    					cnt = 0;
    				}
    				else{
    					cnt = p->val + 1;
    					p = p->go[str[i] - 'a'];
    				}
    			}
    			if (cnt > p->len[0]){
    				p->len[0] = cnt;
    			}
    		}
    		for (int i = tot - 1; i >= 0; i--){
    			if (b[i]->len[0]<b[i]->len[1]) b[i]->len[1] = b[i]->len[0];
    			if (b[i]->suf&&b[i]->suf->len[0]< b[i]->len[0]){
    				b[i]->suf->len[0] = b[i]->len[0];
    			}
    			b[i]->len[0] = 0;
    		}
    	}
    	int ans = 0;
    	for (int i = 0; i < tot; i++){
    		if (ans < b[i]->len[1]){
    			ans = b[i]->len[1];
    		}
    	}
    	printf("%d
    ", ans);
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/chanme/p/3551762.html
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