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  • leetcode mock Shuffle an Array

    1. shuffle算法:

    http://www.cnblogs.com/huaping-audio/archive/2008/09/09/1287985.html

    注意:我们一般用的是第二种swap的方法;但是第一种直接选择,然后把最末尾一位填上的方法,也是很好的。只是会需要两倍的空间。

    2. Random nextInt(bound)参数表示 0-inclusive,bound-exclusive: [0, bound)

    package com.company;
    
    
    import java.util.LinkedList;
    import java.util.List;
    import java.util.Random;
    
    public class Main {
        private int[] orig;
    
        public Main(int[] nums) {
            orig = nums;
        }
    
        /** Resets the array to its original configuration and return it. */
        public int[] reset() {
            return orig;
        }
    
        /** Returns a random shuffling of the array. */
        public int[] shuffle() {
            int[] ret = orig.clone();
            Random rand = new Random();
            for (int i=0; i<ret.length; i++) {
                // int value between 0 (inclusive) and the specified value (exclusive)
                int r = rand.nextInt(ret.length-i);
                if (r != ret.length-i-1) {
                    int k = ret[r];
                    ret[r] = ret[ret.length - i - 1];
                    ret[ret.length - i - 1] = k;
                }
    
            }
            return ret;
        }
    
    
    
        public static void main(String[] args) {
            // write your code here
            System.out.println("Hello");
    
            int []nums = {1,2,3};
            Main obj = new Main(nums);
            int[] param_1 = obj.reset();
            int[] param_2 = obj.shuffle();
            System.out.printf("param_1: %d, %d, %d
    ", param_1[0], param_1[1], param_1[2]);
            System.out.printf("param_2: %d, %d, %d
    ", param_2[0], param_2[1], param_2[2]);
    
        }
    }
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  • 原文地址:https://www.cnblogs.com/charlesblc/p/5936974.html
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