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  • sed 命令运用

    sed 命令:
    echo "I am oldboy,my qq is 1234567" >>oldboy.txt
    要求:
    1、取出oldboy.txt 文件中的oldboy字符串
    方法一:
    [root@git oldboy]# echo "I am oldboy,my qq is 1234567">oldboy.txt
    [root@git oldboy]# cat oldboy.txt
    I am oldboy,my qq is 1234567
    [root@git oldboy]# sed 's#^.*m ##g' oldboy.txt
    oldboy,my qq is 1234567
    [root@git oldboy]# sed 's#^.*m ##g' oldboy.txt |sed 's#,.*##g'
    oldboy
    [root@git oldboy]# sed 's/^.*m //g' oldboy.txt|sed 's/,.*//g'
    oldboy
    注意:"#"和"/"都是替换的符号
    方法二:
    [root@git oldboy]# sed 's#^.*m (oldboy),.*#1#g' oldboy.txt
    oldboy

    [root@git oldboy]# sed 's#^.*m (old)(boy),.*#1#g' oldboy.txt
    old
    [root@git oldboy]# sed 's#^.*m (old)(boy),.*#12#g' oldboy.txt
    oldboy
    [root@git oldboy]# sed 's#^.*m (old)(boy),.*#2#g' oldboy.txt
    boy
    后面加数字的意思是取出前面括号里面的内容,第一个括号表示1,第二个表示2,以此类推。

    要求:
    [root@git oldboy]# cat oldboy.txt
    I am oldboy,my qq is 1234567
    I am old,but am strong
    welcome to test
    去除oldboy.txt中含old不含oldboy的行
    方法一:
    [root@git oldboy]# sed '/old[^boy]/d' oldboy.txt
    I am oldboy,my qq is 1234567
    welcome to test
    方法二:
    [root@git oldboy]# sed '/<old>/d' oldboy.txt
    I am oldboy,my qq is 1234567
    welcome to test
    "<>"匹配单个字符
    将old不含boy的行替换为www.baidu.com
    [root@git oldboy]# sed 's#old[^boy]#www.baidu.com#g' oldboy.txt
    I am oldboy,my qq is 1234567
    I am www.baidu.combut am strong
    welcome to test
    [root@git oldboy]# sed 's#<old>#www.baidu.com#g' oldboy.txt
    I am oldboy,my qq is 1234567
    I am www.baidu.com,but am strong
    welcome to test

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  • 原文地址:https://www.cnblogs.com/cheerong/p/4133493.html
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