2015 HUAS Provincial Select Contest #1~B

11462 Age

Sort You are given the ages (in years) of all people of a country with at least 1 year of age. You know that no individual in that country lives for 100 or more years. Now, you are given a very simple task of sorting all the ages in ascending order.

Input

There are multiple test cases in the input file. Each case starts with an integer n (0 < n ≤ 2000000), the total number of people. In the next line, there are n integers indicating the ages. Input is terminated with a case where n = 0. This case should not be processed.

Output

For each case, print a line with n space separated integers. These integers are the ages of that country sorted in ascending order. Warning: Input Data is pretty big (∼ 25 MB) so use faster IO.

Sample Input

5

3 4 2 1 5

5

2 3 2 3 1

0

Sample Output

1 2 3 4 5

1 2 2 3 3

解题思路：首先是以0为结束标志，所以在输入一个数字之后判断是否为0，再继续进行操作。简单说就是一个排序问题，输入一组数据经过排序后输出，但是这里要注意一个时间问题，如果用cin和cout，那么将很容易时间超出，最好用scanf和printf来进行输入和输出操作，这样才能保证时间在规定的时间内。

程序代码：

#include<cstdio>
#include<algorithm>
using namespace std;
const int maxn=2000000;
 int a[maxn];
int main()
{
   int n,p=1;
  
   while(scanf("%d",&n)==1&&n)
  {
        for(int i=0;i<n;i++)
	   scanf("%d",&a[i]);
		
       for(int z=0;z<n;z++)
           if(a[z]<1||a[z]>=100)    { p=0;   break;}   
	else continue; 
       
	     if(p==1)
              {
		      
                  sort(a,a+n);
	         for(int x=0;x<n-1;x++)
		    printf("%d ",a[x]);
				      
                  printf("%d",a[n-1]);
                  printf("
");
   
              }
  
   }
   return 0;
}