java、struts、tomcat程序中的各种取路径的方法

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http://cffile.sinaapp.com/?p=163

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得到当前路径
File f = new File(".");
String absolutePath = f.getAbsolutePath();
System.out.println(absolutePath);

1.路径中空格:

String pathtem=null;
URL ut=Thread.currentThread().getContextClassLoader().getResource("");
pathtem=ut.toString();
pathtem=pathtem.replace("%20", " ");//去掉空格
pathtem=pathtem.substring(6,pathtem.length());//去掉"file:/"
返回：
d:/apache/webapp/Ev/WEB-INF/classes/

2.生成jar包后
        String pathtem=null;
        URL ut=Csssb_se.class.getResource("");
        pathtem=ut.toString();
        pathtem=pathtem.replace("%20", " ");
        pathtem=pathtem.substring(0,pathtem.indexOf(projectname));
        pathtem=pathtem.replace("file:///","");
        pathtem=pathtem.replace("file:/","");
        pathtem=pathtem.replace("jar:","");
    
3.生成war包后,Tomcat

        String Dirpath = null;
        String Project_name = "TranData";
        URL ut = Thread.currentThread().getContextClassLoader().getResource("");
        Dirpath = ut.toString();
        Dirpath = Dirpath.replace("%20", " ");
        Dirpath = Dirpath.substring(6, Dirpath.length());
        int project_name_index = Dirpath.indexOf(Project_name);
        Dirpath = Dirpath.substring(0, project_name_index
                + Project_name.length() + 1);

        String xmlfilepath = Dirpath + "s.xml";