zoukankan      html  css  js  c++  java
  • [LeetCode] Longest Substring Without Repeating Characters

    Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest substring is "b", with the length of 1.

    用两个指针,一个指向当前子串的头,一个指向尾,尾指针不断往后扫描,当有字符前面出现过了,记录当前子串长度和最优解的比较结果。然后头指针不断往后扫描,直到扫描到一个字符和尾指针相同,则尾指针继续扫描,当尾指针到达字符串结尾,算法结束。复杂度O(n) + O(n) = O(n)

     1 class Solution {
     2 private:
     3     bool canUse[256];
     4 public:
     5     int lengthOfLongestSubstring(string s) {
     6         // Start typing your C/C++ solution below
     7         // DO NOT write int main() function
     8         memset(canUse, true, sizeof(canUse));
     9         
    10         int count = 0;
    11         int start = 0;
    12         int ret = 0;
    13         for(int i = 0; i < s.size(); i++)
    14         {
    15             if (canUse[s[i]])
    16             {
    17                 canUse[s[i]] = false;
    18                 count++;
    19             }
    20             else
    21             {
    22                 ret = max(ret, count);
    23                 while(true)
    24                 {
    25                     canUse[s[start]] = true;
    26                     count--;
    27                     if (s[start] == s[i])
    28                         break;
    29                     start++;
    30                 }
    31                 start++;
    32                 canUse[s[i]] = false;
    33                 count++;
    34             }
    35         }
    36         
    37         ret = max(ret, count);
    38         
    39         return ret;
    40     }
    41 };

     

  • 相关阅读:
    【前端】
    Ember.js 应用入口
    Apache 反向代理实现为http添加https的外衣
    OAuth2.0 四种授权模式
    MongoDB查询重复记录并保存到文件csv
    8000用户同时在线的服务器需求分析
    Bootstrap杂记
    Virtual Box 杂记
    RESTful API你怎么看?
    使用 ASP.NET Core 作为 mediasoup 的信令服务器
  • 原文地址:https://www.cnblogs.com/chkkch/p/2766530.html
Copyright © 2011-2022 走看看