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  • [LeetCode] ZigZag Conversion

    The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

    P   A   H   N
    A P L S I I G
    Y   I   R
    

    And then read line by line: "PAHNAPLSIIGYIR"

    Write the code that will take a string and make this conversion given a number of rows:

    string convert(string text, int nRows);

    convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".

    找到间隔相邻的规律,O(n)的时间可以完成

     1 class Solution {
     2 private:
     3     int step[2];
     4 public:
     5     string convert(string s, int nRows) {
     6         // Start typing your C/C++ solution below
     7         // DO NOT write int main() function    
     8         int steps = 2 * nRows - 2;
     9         
    10         string ret(s);
    11         int retSize = 0;
    12         for(int i = 0; i < nRows; i++)
    13         {
    14             int num = nRows - (i + 1) + nRows - (i + 1) - 1;
    15             num++;
    16             step[0] = num;
    17             if (step[0] == 0)
    18                 step[0] = steps;
    19             step[1] = steps - num;
    20             if (step[1] == 0)
    21                 step[1] = steps;
    22                 
    23             int j = i;
    24             int index = 0;
    25             while(j < s.size())
    26             {
    27                 ret[retSize++] = s[j];
    28                 if (j == j + step[index])
    29                     break;
    30                 j = j + step[index];
    31                 index = 1 - index;
    32             }
    33         }    
    34         
    35         return ret;
    36     }
    37 };

     

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  • 原文地址:https://www.cnblogs.com/chkkch/p/2776132.html
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