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Problem Description
假设：
S1 = 1 S2 = 12 S3 = 123 S4 = 1234 ......... S9 = 123456789 S10 = 1234567891 S11 = 12345678912 ............ S18 = 123456789123456789 .................. 现在我们把所有的串连接起来 S = 1121231234.......123456789123456789112345678912......... 那么你能告诉我在S串中的第N个数字是多少吗？ |
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Input
输入首先是一个数字K，代表有K次询问。
接下来的K行每行有一个整数N(1 <= N < 2^31)。 |
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Output
对于每个N，输出S中第N个对应的数字.
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Sample Input
6 1 2 3 4 5 10 |
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Sample Output
1 1 2 1 2 4 |
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Code The Accepted answer 1 #include <stdio.h> 2 void main() 3 { 4 int i, c, r, sum, count; 5 scanf("%d", &count); 6 while(count --) 7 { 8 sum = 0; 9 scanf("%d", &c); 10 for (i = 0; sum < c; ) 11 sum += ++i; 12 sum -= i; 13 r = c - sum; 14 if (r % 9 == 0) 15 printf("9\n"); 16 else 17 printf("%d\n", r % 9); 18 } 19 } 20 The program which I think it's corrct but don't pass the system 1 #include <stdio.h> 2 #include <math.h> 3 void main() 4 { 5 int count, n, c, r; 6 double tempn; 7 scanf("%d", &count); 8 while (count --) 9 { 10 scanf("%d", &c); 11 tempn = sqrt(2 * c + 1.0 / 4) - 1.0 / 2; 12 n = (int)tempn; 13 if (fabs(tempn - n) <= 1e-6) 14 r = n; 15 else 16 r = c - n * (n + 1) / 2; 17 if (r % 9 == 0) 18 printf("9\n"); 19 else 20 printf("%d\n", r % 9); 21 } 22 } |
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Key Points Firstly, this is my first time using vi to edit and using gcc to compile. So it's necessary to point out some command. gcc *.c then u can get the file named a.out. which I want to stress is that ur name must end with .c. ./a.out then will execute the file. gedit filename u can look the file with a visualization interface, like txt in windown. gcc *.c -lm if ur file contain "#include <math.h>" Secondly, don't forget "fabs". |
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