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  • 20.Valid Parentheses

    题目链接:https://leetcode.com/problems/valid-parentheses/description/

    题目大意:简单的括号 匹配问题。

    法一:栈,代码如下(耗时 9ms):

     1     public boolean isValid(String s) {
     2         char[] str = s.toCharArray();
     3         Stack<Character> stack = new Stack<Character>();
     4         for(int i = 0; i < str.length; i++) {
     5             if(str[i] == '(' || str[i] == '[' || str[i] == '{') {
     6                 stack.push(str[i]);
     7             }
     8             else if(str[i] == ')') {
     9                 if(!stack.isEmpty() && stack.pop() == '(') {
    10                     continue;
    11                 }
    12                 else {
    13                     return false;
    14                 }
    15             }
    16             else if(str[i] == ']') {
    17                 if(!stack.isEmpty() && stack.pop() == '[') {
    18                     continue;
    19                 }
    20                 else {
    21                     return false;
    22                 }
    23             }
    24             else if(str[i] == '}') {
    25                 if(!stack.isEmpty() && stack.pop() == '{') {
    26                     continue;
    27                 }
    28                 else {
    29                     return false;
    30                 }
    31             }
    32         }
    33         if(!stack.isEmpty()) {
    34             return false;
    35         }
    36         return true;
    37     }
    View Code

    法二(借鉴):思想略不同,更简易代码,https://leetcode.com/problems/valid-parentheses/discuss/

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  • 原文地址:https://www.cnblogs.com/cing/p/7759847.html
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