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  • 二维树状数组的区间加减及查询 tyvj 1716 上帝造题的七分钟

    详细解释见小结。http://blog.csdn.net/zmx354/article/details/31740985

    #include <algorithm>
    #include <iostream>
    #include <cstring>
    #include <cstdlib>
    #include <cstdio>
    #include <queue>
    #include <cmath>
    #include <stack>
    #include <map>
    
    #pragma comment(linker, "/STACK:1024000000");
    #define EPS (1e-8)
    #define LL long long
    #define ULL unsigned long long
    #define _LL __int64
    #define _INF 0x3f3f3f3f
    #define Mod 9999991
    #define lowbit(x) (x&(-x))
    
    using namespace std;
    
    const int N = 2049;
    
    int a[N][N];
    int ax[N][N];
    int ay[N][N];
    int axy[N][N];
    
    void Updata(int a[N][N],int x,int y,int n,int m,int data)
    {
        for(; x <= n; x += lowbit(x))
        {
            for(int t = y; t <= m; t += lowbit(t))
            {
                a[x][t] += data;
            }
        }
    }
    
    int Query(int a[N][N],int x,int y)
    {
        int sum = 0;
    
        while(x > 0)
        {
            for(int t = y; t > 0; t -= lowbit(t))
            {
                sum += a[x][t];
            }
            x -= lowbit(x);
        }
    
        return sum;
    }
    
    int sum(int x,int y)
    {
        return Query(a,x,y)*(x+1)*(y+1) - (y+1)*Query(ax,x,y) - (x+1)*Query(ay,x,y) + Query(axy,x,y);
    }
    
    void Add(int x1,int y1,int x2,int y2,int n,int m,int data)
    {
        Updata(a,x1,y1,n,m,data);
        Updata(a,x2+1,y1,n,m,-data);
        Updata(a,x1,y2+1,n,m,-data);
        Updata(a,x2+1,y2+1,n,m,data);
    
        Updata(ax,x1,y1,n,m,x1*data);
        Updata(ax,x2+1,y1,n,m,-(x2+1)*data);
        Updata(ax,x1,y2+1,n,m,-x1*data);
        Updata(ax,x2+1,y2+1,n,m,(x2+1)*data);
    
        Updata(ay,x1,y1,n,m,y1*data);
        Updata(ay,x2+1,y1,n,m,-y1*data);
        Updata(ay,x1,y2+1,n,m,-(y2+1)*data);
        Updata(ay,x2+1,y2+1,n,m,(y2+1)*data);
    
        Updata(axy,x1,y1,n,m,x1*y1*data);
        Updata(axy,x2+1,y1,n,m,-(x2+1)*y1*data);
        Updata(axy,x1,y2+1,n,m,-x1*(y2+1)*data);
        Updata(axy,x2+1,y2+1,n,m,(x2+1)*(y2+1)*data);
    }
    
    int main()
    {
        int n,m;
    
        char order[10];
    
        int x1,x2,y1,y2,data;
    
        memset(a,0,sizeof(a));
        memset(ax,0,sizeof(ax));
        memset(ay,0,sizeof(ay));
        memset(axy,0,sizeof(axy));
    
        while(scanf("%s",order) != EOF)
        {
            if(order[0] == 'L')
            {
                scanf("%d %d %d %d %d",&x1,&y1,&x2,&y2,&data);
    
                Add(x1,y1,x2,y2,n,m,data);
            }
            else if(order[0] == 'k')
            {
                scanf("%d %d %d %d",&x1,&y1,&x2,&y2);
    
                printf("%d
    ",sum(x2,y2) - sum(x1-1,y2) - sum(x2,y1-1) + sum(x1-1,y1-1));
            }
            else
            {
                scanf("%d %d",&n,&m);
            }
        }
    
        return 0;
    }
    


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  • 原文地址:https://www.cnblogs.com/claireyuancy/p/7237823.html
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