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  • linux学习之——数据操作:添加与查询

    说明:

    在linux系统中,利用搭建的服务器,编写两个页面,一个添加信息,一个展现信息;

    主要涉及到:php+mysql的操作;

    数据添加页面:

    <html>
    <head>
    <meta http-equiv='content-type' content='text/html'; charset='utf-8'>
    <title> Test Engineer info table add</title>
    </head>
    
    <body>
    <div align='center'>
    <form action='adduser.php' method='post'>
    
    <h3> Test Engineer_info Table</h3>
    <table width='500' bgcolor='#ccffcc' style='border-color' border='1'>
    <tr align=center><td>name</td><td><input type="text" name="tname"/></td></tr> 
    <tr align=center><td>age</td><td><input type="text" name="tage"/></td></tr> 
    <tr align=center><td>hobby</td><td><input type="text" name="thobby"/></td></tr> 
    <tr align=center> <td>job</td><td><input type="text" name="tjob"/></td></tr> 
    <tr align=center><td colspan='2'><input type="submit" value="add info"></td></tr> 
    </table>
    </form>
    </div> 
    </body>
    </html>

    数据操作:

    <?php
    
     $mysql_server_name= 'localhost';
     $mysql_username='mysqlname';
     $mysql_password='mysqlpassword';
     $mysql_database='mysql-database';
     
     $tname=$_POST[tname];
     $tage=$_POST[tage];
     $thobby=$_POST[thobby];
     $tjob=$_POST[tjob];
     
    
    
     $link = mysql_connect($mysql_server_name,$mysql_username,$mysql_password);
     mysql_query("set names'utf8'");
     
      if (!$link)
         die('could not connect:' .mysql_error());
      else {
            /*echo "LAMP is success!MySql is right!Mysql_database is right";*/
        
            mysql_select_db( $mysql_database,$link);
            if(!empty($tname)){
        $sql_insert="insert into clt_testerinfo values('$tname','$tage','$thobby','$tjob')";
        mysql_query($sql_insert);
        }
             
            $sql_select="select * from  clt_testerinfo";
            $result=mysql_query($sql_select,$link);
         echo "Test Enginner info Table";
         echo '</br>';
         echo "<table width='800' bgcolor='#ccffcc' style='border-color' border='1'>";
         echo "<tr><td>name</td>";
         echo "<td>age</td>";
         echo "<td>hobby</td>";
         echo "<td>job</td></tr>";
        
         while($row = mysql_fetch_array($result))
        {
         echo "<tr><td>";
         echo $row[tname];
         echo "</td><td>";
         echo $row[tage];
         echo "</td><td>";
         echo $row[thobby];
         echo "</td><td>";      
         echo $row[tjob];
         echo "</td></tr>";
        
        }  
         echo "</table>";
        
        }
      mysql_close($link);
    ?>
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  • 原文地址:https://www.cnblogs.com/cloverclt/p/4860508.html
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