u Calculate e
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 39017 Accepted Submission(s): 17700
Problem Description
A simple mathematical formula for e is
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.
Output
Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.
Sample Output
n e
- -----------
0 1
1 2
2 2.5
3 2.666666667
4 2.708333333
Source
#include<stdio.h> double mul(double x) { double sum=1; for(int i=1;i<=x;i++) sum*=i; return sum; } int main() { int j; double i,e=0,k; printf("n e "); printf("- ----------- "); printf("0 1 "); printf("1 2 "); printf("2 2.5 "); for(j=0;j<10;j++) { e+=1/mul(j); if(j>2) printf("%d %11.9f ",j,e); } return 0; }