1.说明: 业务要求,需要知道一个日期是哪个月份的第几周,并且是周一为一周的开始,周一在哪个月,此周就是属于哪个月的;
比如:
2020-02-01 和 2020-02-02属于1月份的第四周 ;
2020-02-03 属于2月份第一周
2.思路: 都2020年了,我们使用JDK8的LocalDate 吧,毕竟真香! API好用~
①找到查询日期sourceTime的当月的第一天(firstDayOfMonth),比如2020-02-01,
②从月初firstDayOfMonth开始找到周一(firstMondayOfMonth)
③比较sourceTime是否 >= firstMondayOfMonth;
④如果true,表示sourceTime就是在当月的周,直接计算firstMondayOfMonth和sourceTime相隔天数,除以7后+1来计算是第几周;
⑤如果false,表示sourceTime就是在上月的周,需要计算上月的第一个周一(firstMondayOfMonth_last),并计算sourceTime和firstMondayOfMonth_last相隔天数,除以7后+1来计算是上月第几周;
⑥return
3.代码如下
获取某个时间的月份第一天(网上copy的)
/** * java8(经测试别的版本获取2月有bug) 获取某月第一天的00:00:00 * * @return */ public static LocalDateTime getFirstLocalDayOfMonth(LocalDateTime localDateTime) { return localDateTime.with(TemporalAdjusters.firstDayOfMonth()).with(LocalTime.MIN); }
获取汉字版月份(这个是自己的笨法子)
/** * 获取汉字版月份 * * @param monthNo 第几月 * @return */ public static String getMonthChinese(int monthNo) { switch (monthNo) { case 1: return "一"; case 2: return "二"; case 3: return "三"; case 4: return "四"; case 5: return "五"; case 6: return "六"; case 7: return "七"; case 8: return "八"; case 9: return "九"; case 10: return "十"; case 11: return "十一"; case 12: return "十二"; default: break; } return null; }
获取几月份的第几周(核心方法)
/** * 获取几月份的第几周 [X月份第X周] * * @param sourceTime 这个推荐取00:00:00时间 * @return */ public static Map<String, Object> getMonthNoAndWeekNo(LocalDateTime sourceTime) { Map<String, Object> map = new HashMap<>(); String monthNoAndWeekNo = null; //获取当月的第一天 LocalDateTime firstDayOfMonth = getFirstLocalDayOfMonth(sourceTime); //获取月第一天开始的周一,从当月第一天开始找 LocalDateTime firstMondayOfMonth = firstDayOfMonth; for (int i = 0; i < 6; i++) { DayOfWeek dayOfWeekTemp = firstMondayOfMonth.getDayOfWeek(); if (dayOfWeekTemp.equals(DayOfWeek.MONDAY)) { break; } //往后推一天 firstMondayOfMonth = firstMondayOfMonth.plusDays(1); } //比较当月的第一个星期一 < = 参数时间 if (!firstMondayOfMonth.isBefore(sourceTime)) { //如果当月的第一个周一大于参数时间,则要计算到上个月份去 //获取上一个月的第一个周一 LocalDateTime lastMontLocalDateTime = sourceTime.minusMonths(1); //上个月的第一天 LocalDateTime firstDayOfMonth_last = getFirstLocalDayOfMonth(lastMontLocalDateTime); //从上个月的第一天开始找周一 LocalDateTime firstMondayOfMonth_last = firstDayOfMonth_last; for (int i = 0; i < 6; i++) { DayOfWeek dayOfWeekTemp = firstMondayOfMonth_last.getDayOfWeek(); if (dayOfWeekTemp.equals(DayOfWeek.MONDAY)) { break; } //往后推一天 firstMondayOfMonth_last = firstMondayOfMonth_last.plusDays(1); } // 计算两个时间间隔天数 (上月第一个周一 减去 当前时间) Duration duration = Duration.between(firstMondayOfMonth_last, sourceTime); long diffDays = duration.toDays(); //相差的天数 //第几周weekNo long weekNo = (diffDays / 7) + 1; //月份 int monthNo = firstMondayOfMonth_last.getMonth().getValue();//汉字版月份 String monthChinese = getMonthChinese(monthNo); monthNoAndWeekNo = monthChinese + "月份" + "第" + weekNo + "周"; map.put("monthNo", monthNo); map.put("weekNo", weekNo); map.put("monthNoAndWeekNo", monthNoAndWeekNo); } else { //当月第一个周一在当前时间之前 firstMondayOfMonth<=sourceTime //计算两个时间间隔天数 int dayOfMonthFirstMonday = firstMondayOfMonth.getDayOfMonth(); int dayOfMonthSourceTime = sourceTime.getDayOfMonth(); int diffDays = dayOfMonthSourceTime - dayOfMonthFirstMonday; //第几周weekNo int weekNo = (diffDays / 7) + 1; //月份 int monthNo = sourceTime.getMonth().getValue(); map.put("monthNo", monthNo); map.put("weekNo", weekNo); //汉字版月份 String monthChinese = getMonthChinese(monthNo); monthNoAndWeekNo = monthChinese + "月份" + "第" + weekNo + "周"; map.put("monthNoAndWeekNo", monthNoAndWeekNo); } return map; }
4.测试
public static void main(String[] args) { DateTimeFormatter df = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss"); LocalDateTime sourceTime = LocalDateTime.parse("2020-02-03 17:07:05", df); Map<String, Object> weekNoOfMonth = getMonthNoAndWeekNo(sourceTime); System.out.println("weekNoOfMonth :" + weekNoOfMonth); LocalDateTime sourceTime2 = LocalDateTime.parse("2020-02-16 17:07:05", df); Map<String, Object> weekNoOfMonth2 = getMonthNoAndWeekNo(sourceTime2); System.out.println("weekNoOfMonth2 :" + weekNoOfMonth2); LocalDateTime sourceTime3 = LocalDateTime.parse("2020-02-01 17:07:05", df); Map<String, Object> weekNoOfMonth3 = getMonthNoAndWeekNo(sourceTime3); System.out.println("weekNoOfMonth3 :" + weekNoOfMonth3); }
结果如下:
weekNoOfMonth :{monthNo=2, weekNo=1, monthNoAndWeekNo=二月份第1周} weekNoOfMonth2 :{monthNo=2, weekNo=2, monthNoAndWeekNo=二月份第2周} weekNoOfMonth3 :{monthNo=1, weekNo=4, monthNoAndWeekNo=一月份第4周}
5.总结
上面逻辑应该可以优化~