#!/bin/bash
# Crushlinux
# 2017-03-10
for one in {1..9}
do
for ((two=1;two<=$one;two++))
do
echo -n "$two x $one = $(($one*$two)) "
done
echo
done
版本二:
#!/bin/bash
#99乘法表
for i in {1..9}
do
for j in {1..9}
do
echo -n "$j*$i=$(expr $j * $i) "
if [ $j == $i ];then
echo -e '
' #-e 允许对后面做出解释
break
fi
done
done
版本三:
#!/bin/bash
for i in {1..9}
do
for j in {1..9}
do
if [ $j -le $i ]
then
echo -n "$j x $i = $(($j*$i)) "
fi
done
echo
done
