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  • 学习笔记二叉树排序,面试经常考的题目

    二叉树代码

    代码
    using System;

    namespace System.MySortNS
    {
    //表示二叉树,所有树节点根据严格的二叉规则聚合得到的集合
    public sealed class BinaryTree
    {
    //二叉树节点
    sealed class TreeNode
    {
    private int _nodevalue;//节点值
    private TreeNode _leftnode;//左子节点
    private TreeNode _rightnode;//右子节点

    public TreeNode(int nodevalue)
    {
    this._nodevalue = nodevalue;
    this._leftnode = null;
    this._rightnode = null;
    }
    public int NodeValue
    {
    get
    {
    return this._nodevalue;
    }
    }
    public TreeNode LeftNode
    {
    get
    {
    return this._leftnode;
    }
    set
    {
    if (value != null)
    {
    if (this.LeftNode == null)
    {
    this._leftnode = value;
    }
    else
    {
    //nothing to do here!
    }
    }
    else
    {
    //nothing to do here!
    }
    }
    }
    public TreeNode RightNode
    {
    get
    {
    return this._rightnode;
    }
    set
    {
    if (value != null)
    {
    if (this.RightNode == null)
    {
    this._rightnode = value;
    }
    else
    {
    //nothing to do here!
    }
    }
    else
    {
    //nothing to do here!
    }
    }
    }
    }

    private TreeNode _rootnode;//根节点

    public BinaryTree()
    {
    this._rootnode = null;
    }

    public void AddNumber(int num)
    {
    if (this._rootnode == null)//尚未有根节点时,新节点自然占据根节点的地位
    {
    this._rootnode = new TreeNode(num);
    }
    else
    {
    TreeNode newnode
    = new TreeNode(num);
    TreeNode currentnode
    = this._rootnode;
    this.addTreeNode(newnode, currentnode);
    }
    }
    //递归方法,在已存在的树中寻找新节点的合理位置并添加
    //需要了解的数据:待添加节点,当前操作到的节点
    //添加规则:与当前节点比较,小向左,大向右,先来着为大
    private void addTreeNode(TreeNode node,TreeNode currentnode)
    {
    if (node.NodeValue <= currentnode.NodeValue)//后来者为小,向左走
    {
    if (currentnode.LeftNode == null)
    {
    currentnode.LeftNode
    = node;
    //done!
    }
    else//转换比较场地,继续递归比较
    {
    this.addTreeNode(node,currentnode.LeftNode);
    }
    }
    else//后来者大了,向右走
    {
    if (currentnode.RightNode == null)
    {
    currentnode.RightNode
    = node;
    //done!
    }
    else//转换比较场地,继续递归比较
    {
    this.addTreeNode(node, currentnode.RightNode);
    }
    }
    }

    //使用中序遍历,获取已添加的二叉树之有序节点值结果
    public System.Collections.Generic.List<int> GetSortedList()
    {
    System.Collections.Generic.List
    <int> list;
    list
    = new System.Collections.Generic.List<int>();
    //递归进行中序遍历,获取有序数据,填充到已定义的动态数组中
    TreeNode currentnode = this._rootnode;
    this.fillNumber(currentnode, list);

    return list;
    }
    //递归中序遍历填充方法
    private void fillNumber(TreeNode currentnode, System.Collections.Generic.List<int> list)
    {
    if (currentnode != null)
    {
    //递归遍历左分支
    this.fillNumber(currentnode.LeftNode, list);
    //访问并填充当前节点值
    list.Add(currentnode.NodeValue);
    //递归遍历右分支
    this.fillNumber(currentnode.RightNode, list);
    }
    else//下级节点为空,不予继续处理本次分支
    {
    //nothing to do here!
    }
    }
    }

    class Program
    {
    static void Main(string[] args)
    {
    string input = null;
    Console.WriteLine(
    "请逐次输入希望参与排序的整数,输入EXIT则结束!");
    int num = 0;

    BinaryTree tree
    = new BinaryTree();
    while (true)
    {
    Console.Write(
    "请输入整数:");
    input
    = Console.ReadLine();
    if (input.Trim().ToUpper() == "EXIT")
    {
    Console.WriteLine(
    "添加结束!");
    break;
    }
    else
    {
    //nothing to do here!
    }
    num
    = Int32.Parse(input);
    tree.AddNumber(num);
    }
    Console.WriteLine(
    "如想要看到排序后的列表,请回车!");
    Console.ReadLine();
    Console.Write(
    "\n---------------------------\n");
    System.Collections.Generic.List
    <int> result = tree.GetSortedList();
    foreach (int n in result)
    {
    Console.Write(n.ToString());
    Console.Write(
    "\t");
    }
    Console.Write(
    "\n---------------------------\n");
    }
    }
    }
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  • 原文地址:https://www.cnblogs.com/cs_net/p/1837971.html
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