2018HDU多校训练一 K

Chiaki often participates in international competitive programming contests. The time zone becomes a big problem. 
Given a time in Beijing time (UTC +8), Chiaki would like to know the time in another time zone ss. 

Input

There are multiple test cases. The first line of input contains an integer TT (1≤T≤1061≤T≤106), indicating the number of test cases. For each test case: 
The first line contains two integers aa, bb (0≤a≤23,0≤b≤590≤a≤23,0≤b≤59) and a string ss in the format of "UTC+X'', "UTC-X'', "UTC+X.Y'', or "UTC-X.Y'' (0≤X,X.Y≤14,0≤Y≤90≤X,X.Y≤14,0≤Y≤9).

Output

For each test, output the time in the format of hh:mmhh:mm (24-hour clock). 

Sample Input

3
11 11 UTC+8
11 12 UTC+9
11 23 UTC+0

Sample Output

11:11
12:12
03:23

题解：就是时区时间的转换，用sscanf(s+4."%lf",&d);将小数还原到数字d;

算出0时区的时间，再转化8时区即可；

#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
const LL inf=0x3f3f3f3f3f3f3f3fLL;
const int INF=0x3f3f3f3f;
int T,a,b;
char s1[10];
int main()
{
	
	scanf("%d",&T);
	while(T--)
	{
		scanf("%d%d",&a,&b);
		int sum=a*60+b;
		scanf("%s",s1);
		double x;
		int num= s1[3]=='+'? 1:-1;
		sscanf(s1+4,"%lf",&x);
		int cx=(int)(10*x);
		sum=sum+cx*num*6-8*60;
		int h=sum%(24*60);
		if(h<0) h+=24*60;
		printf("%02d:%02d
",h/60,h%60);
		
	}
	
	
	return 0;
}