在线正则表达式匹配:http://tool.oschina.net/regex
正则表达式学习:https://c.runoob.com/front-end/854
一、什么是正则表达式?
常见匹配模式
模式 | 描述 |
w | 匹配字母数字及下划线 |
W | 匹配非字母数字下划线 |
s | 匹配任意空白字符,等价于[ f] |
S | 匹配任意非空字符 |
d | 匹配任意数字,等价于[0-9] |
D | 匹配任意非数字 |
A | 匹配字符串开始 |
匹配字符串结束,如果时存在换行,之匹配到换行前的结束字符串 | |
z | 匹配字符串结束 |
G | 匹配最后匹配完成的位置 |
匹配一个换行符 | |
匹配一个制表符 | |
^ | 匹配字符串的开头 |
$ | 匹配字符串的末尾 |
. | 匹配任意字符,除了换行符,当re.DOTTALL标记被指定时,则可以匹配包括换行符的任意字符 |
[...] | 用来表示一组字符,单独列出:[amk]匹配'a','m'或'k' |
[^...] | 不再[]中的字符,单独列出:[^abc]匹配除了a,b,c之外的字符 |
* | 匹配0个或多个的表达式 |
+ | 匹配1个或多个的表达式 |
? | 匹配0个或1个由前面的正则表达式定义的片段,非贪婪模式 |
(n) | 精确匹配n个前面表达式 |
(n,m) | 匹配n到m次由前面的正则表达式定义的片段,贪婪方式 |
a|b | 匹配a或b |
() | 匹配括号内的表达式,也表示一个组 |
re.match
re.match尝试从字符串的起始位置匹配一个模式,如果不是起始位置匹配成功的话,match()就返回none.
re.match(pattern,string,flags=0)
最常规的匹配
import re content = 'Hello 123 4567 World_This is a Regex Demo' print(len(content)) result = re.match('^Hellosd{3}sd{4}sw{10}.*Demo$',content) print(result) print(result.group()) print(result.span())
泛匹配
import re content = 'Hello 123 4567 World_This is a Regex Demo' result = re.match('^Hello.*Demo$',content) print(result) print(result.group()) print(result.span())
匹配目标
import re content = 'Hello 1234567 World_This is a Regex Demo' result = re.match('^Hellos(d+)sWorld.*Demo$',content) print(result) print(result.group(1)) print(result.span())
贪婪匹配
import re content = 'Hello 1234567 World_This is a Regex Demo' result = re.match('^He.*(d+).*Demo$',content) print(result) print(result.group(1)) print(result.span())
非贪婪匹配
import re content = 'Hello 1234567 World_This is a Regex Demo' result = re.match('^He.*?(d+).*Demo$',content) print(result) print(result.group(1)) print(result.span())
匹配模式
import re content = '''Hello 1234567 World_This is a Regex Demo''' result = re.match('^He.*?(d+).*?Demo$',content,re.S)# .不能匹配换行符,re.S来支持匹配换行符 print(result) print(result.group(1))
转义
import re content = 'price is $5.00' result = re.match('price is $5.00',content) print(result)
总结:尽量使用泛匹配、使用括号得到匹配目标、尽量使用非贪婪模式、有换行符就用re.S
re.search
re.search 扫描整个字符串并返回第一个成功的匹配
import re content = 'Extra strings Hello 1234567 World_This is a Regex Demo Extra strings' result = re.match('Hello.*?(d+).*?Demo',content) print(result)
import re content = 'Extra strings Hello 1234567 World_This is a Regex Demo Extra strings' result = re.search('Hello.*?(d+).*?Demo',content) print(result)
总结:为了匹配方便,能用search就不用match
匹配练习
import re html = ''' <div id="songs-list"> <h2 class="title">金典老歌</h2> <p class="introduction">金典老歌列表</p> <ul i="list" class="list-group"> <li data-view="2">一路有你</li> <li data-view="7"> <a href="/2.mp3" singer="任贤齐">沧海一声笑</a> </li> <li data-view="4" class="active"> <a href="/3.mp3" singer="齐秦">往事随风</a> </li> <li data-view="6"><a href="4.mp3" singer="beyond">光辉岁月</a></li> <li data-view="5"><a href="5.mp3" singer="陈慧琳">记事本</a></li> <li data-view="5"> <a href="6.mp3" singer="邓丽君"><i class="fa fa-user"></i>但愿人长久</a> </li> </ul> </div> ''' result = re.search('<li.*?active.*?singer="(.*?)">(.*?)</a>',html,re.S) if result: print(result.group(1),result.group(2)) else: print("ok")
import re html = ''' <div id="songs-list"> <h2 class="title">金典老歌</h2> <p class="introduction">金典老歌列表</p> <ul i="list" class="list-group"> <li data-view="2">一路有你</li> <li data-view="7"> <a href="/2.mp3" singer="任贤齐">沧海一声笑</a> </li> <li data-view="4" class="active"> <a href="/3.mp3" singer="齐秦">往事随风</a> </li> <li data-view="6"><a href="4.mp3" singer="beyond">光辉岁月</a></li> <li data-view="5"><a href="5.mp3" singer="陈慧琳">记事本</a></li> <li data-view="5"> <a href="6.mp3" singer="邓丽君"><i class="fa fa-user"></i>但愿人长久</a> </li> </ul> </div> ''' result = re.search('<li.*?singer="(.*?)">(.*?)</a>',html,re.S) if result: print(result.group(1),result.group(2)) else: print("ok")
import re html = ''' <div id="songs-list"> <h2 class="title">金典老歌</h2> <p class="introduction">金典老歌列表</p> <ul i="list" class="list-group"> <li data-view="2">一路有你</li> <li data-view="7"> <a href="/2.mp3" singer="任贤齐">沧海一声笑</a> </li> <li data-view="4" class="active"> <a href="/3.mp3" singer="齐秦">往事随风</a> </li> <li data-view="6"><a href="4.mp3" singer="beyond">光辉岁月</a></li> <li data-view="5"><a href="5.mp3" singer="陈慧琳">记事本</a></li> <li data-view="5"> <a href="6.mp3" singer="邓丽君"><i class="fa fa-user"></i>但愿人长久</a> </li> </ul> </div> ''' result = re.search('<li.*?singer="(.*?)">(.*?)</a>',html) if result: print(result.group(1),result.group(2)) else: print("ok")
re.findall
搜索字符串,一列表形式返回全部能匹配的字串
import re html = ''' <div id="songs-list"> <h2 class="title">金典老歌</h2> <p class="introduction">金典老歌列表</p> <ul i="list" class="list-group"> <li data-view="2">一路有你</li> <li data-view="7"> <a href="/2.mp3" singer="任贤齐">沧海一声笑</a> </li> <li data-view="4" class="active"> <a href="/3.mp3" singer="齐秦">往事随风</a> </li> <li data-view="6"><a href="/4.mp3" singer="beyond">光辉岁月</a></li> <li data-view="5"><a href="/5.mp3" singer="陈慧琳">记事本</a></li> <li data-view="5"> <a href="/6.mp3" singer="邓丽君">但愿人长久</a> </li> </ul> </div> ''' results = re.findall('<li.*?href="(.*?)".*?singer="(.*?)">(.*?)</a>',html,re.S) print(results) print(type(results)) for result in results: print(result) print(result[0],result[1],result[2])
import re html = ''' <div id="songs-list"> <h2 class="title">金典老歌</h2> <p class="introduction">金典老歌列表</p> <ul i="list" class="list-group"> <li data-view="2">一路有你</li> <li data-view="7"> <a href="/2.mp3" singer="任贤齐">沧海一声笑</a> </li> <li data-view="4" class="active"> <a href="/3.mp3" singer="齐秦">往事随风</a> </li> <li data-view="6"><a href="/4.mp3" singer="beyond">光辉岁月</a></li> <li data-view="5"><a href="/5.mp3" singer="陈慧琳">记事本</a></li> <li data-view="5"> <a href="/6.mp3" singer="邓丽君">但愿人长久</a> </li> </ul> </div> ''' results = re.findall('<li.*?>s*?(<a.*?>)?(w+)(</a>?s*?</li)',html,re.S) print(results) for result in results: print(result[1])
re.sub
替换字符串中每一个匹配的子串后返回替换后的字符串
import re content = 'Extra strings Hello 1234567 World_This is a Regex Demo Extra strings' content = re.sub('d+','',content) print(content)
import re content = 'Extra strings Hello 1234567 World_This is a Regex Demo Extra strings' content = re.sub('d+','Reldjaidja',content) # 将d+所在位置替换成Reldjaidja print(content)
import re content = 'Extra strings Hello 1234567 World_This is a Regex Demo Extra strings' content = re.sub('(d+)',r'1 8910',content) # 1是将第一个括号里的内容作了替换 print(content)
import re html = ''' <div id="songs-list"> <h2 class="title">金典老歌</h2> <p class="introduction">金典老歌列表</p> <ul i="list" class="list-group"> <li data-view="2">一路有你</li> <li data-view="7"> <a href="/2.mp3" singer="任贤齐">沧海一声笑</a> </li> <li data-view="4" class="active"> <a href="/3.mp3" singer="齐秦">往事随风</a> </li> <li data-view="6"><a href="/4.mp3" singer="beyond">光辉岁月</a></li> <li data-view="5"><a href="/5.mp3" singer="陈慧琳">记事本</a></li> <li data-view="5"> <a href="/6.mp3" singer="邓丽君">但愿人长久</a> </li> </ul> </div> ''' html = re.sub('<a.*?>|</a>','',html) print(html) results = re.findall('<li.*?>(.*?)</li>',html,re.S) print(results) for result in results: print(result.strip())
re.compile
将正则字符串编译成正则表达式对象:
将一个正则表达式串编译成正则对象,以便于复用该匹配模式
import re content = '''Hello 1234567 World_Tis is a Regex Demo ''' # 第一种 pattern = re.compile('Hello.*Demo',re.S) result = re.match(pattern,content) print(result) #第二种 result = re.match('Hello.*Demo',content,re.S) print(result)
练习:爬去豆瓣图书的图书信息
import requests import re content = requests.get('https://book.douban.com').text pattern = re.compile('<li.*?"cover".*?href="(.*?)".*?title="(.*?)".*?more-meta">.*?"author">(.*?)</span>.*?"year">(.*?)</span>.*?"publisher">(.*?)</span>.*?</li>',re.S) print(pattern) results = re.findall(pattern,content) print(results) for ret in results: url,title,author,date,publisher = ret author = re.sub('s','',author) date=re.sub('s','',date) publisher=re.sub('s','',publisher) print(url,title,author,date,publisher)