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  • Leetcode 34

    //二分查找后,向两边扩展,二分错了两次,现在是对的。
    //还有就是vector可以用{}直接赋值很棒

    class
    Solution { public: vector<int> searchRange(vector<int>& nums, int target) { int left = 0; int right = nums.size()-1; int mid = -1; bool flag = false; while(left<=right){ mid = (left+right)/2; if(nums[mid] == target){flag = true;break;} else if(nums[mid] < target){left = mid+1;} else{right = mid-1;} } if(flag == false) return {-1,-1}; int begin = mid; while(begin >= 0){ if(nums[begin] != target) break; begin--; } begin++; int end = mid; while(end < nums.size()){ if(nums[end] != target)break; end++; } end--; return {begin,end}; } };
    //递归的二分
    int
    search(vector<int>& nums, int left, int right, int target) { if (left > right) return -1; int mid = left + (right - left) / 2; if (nums[mid] == target) return mid; else if (nums[mid] < target) return search(nums, mid + 1, right, target); else return search(nums, left, mid - 1, target); }
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  • 原文地址:https://www.cnblogs.com/cunyusup/p/9668889.html
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