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  • 挑战编程

    第一章 入门

    Chapter 1

    100 - The 3n + 1 problem


    #include <iostream>
    #include <cstdio>
    #include <cstring>
    
    using namespace std;
    
    const int maxn=1111111;
    
    int f[maxn];
    
    int main()
    {
        int x,y;
        int ans,ret;
        memset(f,0,sizeof(f));
        while (~scanf("%d%d",&x,&y))
        {
            ans=0;
            for (int i=min(x,y);i<=max(x,y);i++)
            {
                if (f[i]) ret=f[i];
                else
                {
                    ret=1;
                    int n=i;
                    while (n!=1)
                    {
                        if (n&1) n=3*n+1;
                        else n/=2;
                        ret++;
                    }
                    f[i]=ret;
                }
                if (ret>ans) ans=ret;
            }
            printf("%d %d %d\n",x,y,ans);
        }
        return 0;
    }


    10189 - Minesweeper


    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    
    using namespace std;
    
    const int direct[8][2]={ {1,0},{-1,0},{0,1},{0,-1},{1,1},{-1,1},{1,-1},{-1,-1} };
    
    char s[111][111];
    int f[111][111];
    int n,m;
    
    bool check(int x,int y)
    {
        if (x>=1&&x<=n&&y>=1&&y<=m) return true;
        return false;
    }
    
    int main()
    {
        int cnt=0;
        while (~scanf("%d%d",&n,&m))
        {
            if (n==0&&m==0) break;
            memset(f,0,sizeof(f));
            for (int i=1;i<=n;i++)
            {
                scanf("%s",s[i]+1);
            }
            for (int i=1;i<=n;i++)
            {
                for (int j=1;j<=m;j++)
                {
                    if (s[i][j]=='*')
                    {
                        for (int k=0;k<8;k++)
                        {
                            int x=i+direct[k][0];
                            int y=j+direct[k][1];
                            if (check(x,y)) f[x][y]++;
                        }
                    }
                }
            }
            if (cnt>0) puts("");
            printf("Field #%d:\n",++cnt);
            for (int i=1;i<=n;i++)
            {
                for (int j=1;j<=m;j++)
                {
                    if (s[i][j]=='*') printf("*");
                    else printf("%d",f[i][j]);
                }
                printf("\n");
            }
        }
        return 0;
    }



    10137 - The Trip


    #include <iostream>
    #include <cstdio>
    #include <cstring>
    
    using namespace std;
    
    const int maxn=111111;
    double a[maxn];
    
    int main()
    {
        int n;
        double sum,avg,ans1,ans2;
        while (~scanf("%d",&n))
        {
            if (n==0) break;
            sum=0;
            for (int i=0;i<n;i++)
            {
                scanf("%lf",&a[i]);
                sum+=a[i];
            }
            avg=sum/n;
            ans1=0;
            ans2=0;
            for (int i=0;i<n;i++)
            {
                if (a[i]<avg) ans1+=double(int((avg-a[i])*100))/100.0;
                if (avg<a[i]) ans2+=double(int((a[i]-avg)*100))/100.0;
            }
            printf("$%0.2f\n",max(ans1,ans2));
        }
        return 0;
    }



    10267 - Graphical Editor

    #include <iostream>
    #include <cstring>
    #include <cstdio>
    #include <algorithm>
    #include <queue>
    
    using namespace std;
    
    const int direct[4][2]={ {0,1},{1,0},{0,-1},{-1,0} };
    char map[333][333];
    int n,m;
    
    void set(char c)
    {
        for (int i=1; i<=n; i++)
        {
            for (int j=1; j<=m; j++)
            {
                map[i][j]=c;
            }
        }
    }
    
    void print(int x1,int y1,int x2,int y2,char c)
    {
        for (int i=y1;i<=y2&&i<=n;i++)
        {
            for (int j=x1;j<=x2&&j<=m;j++)
            {
                map[i][j]=c;
            }
        }
    }
    
    struct POINT{
        int x;
        int y;
    };
    
    
    int main()
    {
        char c,chr;
        int x,y;
        int x1,x2,y1,y2;
        char name[333];
        while (cin>>c)
        {
            if (c=='X') break;
            else if (c=='I')
            {
                cin>>m>>n;
                set('O');
            }
            else if (c=='C')
            {
                set('O');
            }
            else if (c=='L')
            {
                cin>>x>>y>>chr;
                map[y][x]=chr;
            }
            else if (c=='V')
            {
                cin>>x>>y1>>y2>>chr;
                if (y1>y2) swap(y1,y2);
                print(x,y1,x,y2,chr);
            }
            else if (c=='H')
            {
                cin>>x1>>x2>>y>>chr;
                if (x1>x2) swap(x1,x2);
                print(x1,y,x2,y,chr);
            }
            else if (c=='K')
            {
                cin>>x1>>y1>>x2>>y2>>chr;
                if (x1>x2) swap(x1,x2);
                if (y1>y2) swap(y1,y2);
                print(x1,y1,x2,y2,chr);
            }
            else if (c=='F')
            {
                cin>>x>>y>>chr;
                queue<POINT>que;
                while (!que.empty()) que.pop();
                POINT p;
                p.x=y;
                p.y=x;
                char tel=map[p.x][p.y];
                if (tel==chr) continue;
                que.push(p);
                map[p.x][p.y]=chr;
                while (!que.empty())
                {
                    POINT tmp=que.front();
                    que.pop();
                    for (int i=0;i<4;i++)
                    {
                        p.x=tmp.x+direct[i][0];
                        p.y=tmp.y+direct[i][1];
                        if (p.x>=1&&p.x<=n&&p.y>=1&&p.y<=m&&map[p.x][p.y]==tel)
                        {
                            map[p.x][p.y]=chr;
                            que.push(p);
                        }
                    }
                }
            }
            else if (c=='S')
            {
                cin>>name;
                cout<<name<<endl;
                for (int i=1;i<=n;i++)
                {
                    for (int j=1;j<=m;j++)
                    {
                        cout<<map[i][j];
                    }
                    cout<<endl;
                }
            }
            else
            {
                continue;
            }
        }
        return 0;
    }



    第二章 数据结构

    Chapter 2


    10038 - Jolly Jumpers

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    
    using namespace std;
    
    const int maxn=3333;
    bool v[maxn];
    int a[maxn];
    int n;
    int sum;
    
    int main()
    {
        while (cin>>n)
        {
            sum=0;
            memset(v,0,sizeof(v));
            for (int i=1;i<=n;i++) cin>>a[i];
            for (int i=2;i<=n;i++)
            {
                int t=abs(a[i]-a[i-1]);
                if (!v[t]&&t>=1&&t<=n-1)
                {
                    v[t]=true;
                    sum++;
                }
            }
            if (sum==n-1) puts("Jolly");
            else puts("Not jolly");
        }
        return 0;
    }



    第三章 字符串

    Chapter 3


    10010 - Where's Waldorf?


    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <ctype.h>
    using namespace std;
    
    const int direct[8][2]= { {0,1},{1,0},{0,-1},{-1,0},{1,1},{1,-1},{-1,1},{-1,-1} };
    
    char map[55][55];
    int n,m;
    bool v[55][55];
    char s[55];
    int len;
    
    bool check(int x,int y)
    {
        if (x>=1&&x<=n&&y>=1&&y<=m) return true;
        return false;
    }
    
    bool dfs(int x,int y,int deep,int g)
    {
        if (deep>=len) return true;
        if (!check(x,y)) return false;
        if (map[x][y]!=s[deep]) return false;
        int dx=x+direct[g][0];
        int dy=y+direct[g][1];
        if (dfs(dx,dy,deep+1,g)) return true;
        return false;
    }
    
    int main()
    {
        int T,k;
        cin>>T;
        while (T--)
        {
            cin>>n>>m;
            for (int i=1; i<=n; i++) cin>>(map[i]+1);
            for (int i=1; i<=n; i++) for (int j=1; j<=m; j++)
                if (islower(map[i][j])) map[i][j]=toupper(map[i][j]);
            cin>>k;
            //for (int i=1; i<=n; i++) cerr<<(map[i]+1)<<endl;
            while (k--)
            {
                int i,j,g;
                bool ok=false;
                cin>>s;
                len=strlen(s);
                for (i=0; i<len; i++)
                    if (islower(s[i])) s[i]=toupper(s[i]);
                //cerr<<s<<endl;
                for (i=1; i<=n; i++)
                {
                    for (j=1; j<=m; j++)
                    {
                        for (g=0; g<8; g++)
                        {
                            if (dfs(i,j,0,g))
                            {
                                ok=true;
                                cout<<i<<" "<<j<<endl;
                                break;
                            }
                        }
                        if (ok) break;
                    }
                    if (ok) break;
                }
            }
            if (T) cout<<endl;
        }
        return 0;
    }

    10188 - Automated Judge Script


    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <string>
    #include <vector>
    
    using namespace std;
    
    vector<string>ac,sub;
    int n,m;
    
    bool accepted()
    {
        for (int i=0;i<n;i++)
        {
            if (ac[i]!=sub[i]) return false;
        }
        return true;
    }
    
    bool PE()
    {
        string num;
        string ans;
        num.clear();
        ans.clear();
        for (int i=0;i<n;i++)
        {
            for (int j=0;j<ac[i].size();j++)
            {
                if (isdigit(ac[i][j])) num+=ac[i][j];
            }
        }
        for (int i=0;i<m;i++)
        {
            for (int j=0;j<sub[i].size();j++)
            {
                if (isdigit(sub[i][j])) ans+=sub[i][j];
            }
        }
        if (ans==num) return true;
        /*
        cerr<<"---"<<ans<<"---"<<num<<"---";
        if(ans==num) cerr<<"same"<<endl;
        else cerr<<"not"<<endl;
        */
        return false;
    }
    
    int main()
    {
        string s;
        int cnt=0;
        while (cin>>n)
        {
            if (n==0) break;
            ac.clear();
            sub.clear();
            getchar();
            for (int i=0;i<n;i++)
            {
                getline(cin,s);
                ac.push_back(s);
            }
            cin>>m;
            getchar();
            for (int i=0;i<m;i++)
            {
                getline(cin,s);
                sub.push_back(s);
            }
            if (n==m&&accepted())
            {
                cout<<"Run #"<<++cnt<<": Accepted"<<endl;
            }
            else if (PE())
            {
                cout<<"Run #"<<++cnt<<": Presentation Error"<<endl;
            }
            else
            {
                cout<<"Run #"<<++cnt<<": Wrong Answer"<<endl;
            }
        }
        return 0;
    }
    




    第四章 排序

    Chapter 4


    10041 - Vito's Family


    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    
    using namespace std;
    
    int a[555];
    int n;
    
    int main()
    {
        int T;
        int ans;
        cin>>T;
        while (T--)
        {
            cin>>n;
            ans=0;
            for (int i=1;i<=n;i++) cin>>a[i];
            sort(a+1,a+n+1);
            int m=n/2+1;
            for (int i=1;i<=n;i++) ans+=abs(a[i]-a[m]);
            cout<<ans<<endl;
        }
        return 0;
    }
    


    第五章 算数与代数

    Chapter 5


    10035 - Primary Arithmetic


    #include <iostream>
    #include <cstdio>
    #include <cstring>
    
    using namespace std;
    
    int a[111];
    int b[111];
    char sa[111];
    char sb[111];
    int lena,lenb;
    
    int main()
    {
        while (cin>>sa>>sb)
        {
            if (strcmp(sa,sb)==0&&strcmp(sa,"0")==0) break;
            memset(a,0,sizeof(a));
            memset(b,0,sizeof(b));
            lena=strlen(sa);
            lenb=strlen(sb);
            for (int i=0;i<lena;i++) a[i]=sa[lena-i-1]-'0';
            for (int i=0;i<lenb;i++) b[i]=sb[lenb-i-1]-'0';
            int ans=0;
            for (int i=0;i<max(lena,lenb);i++)
            {
                a[i]+=b[i];
                if (a[i]>=10)
                {
                    a[i+1]+=1;
                    a[i]-=10;
                    ans++;
                }
            }
            if (ans==1) cout<<ans<<" carry operation."<<endl;
            else if (ans>1) cout<<ans<<" carry operations."<<endl;
            else cout<<"No carry operation."<<endl;
        }
        return 0;
    }




    第六章 组合数学

    Chapter 6




    第七章 数论

    Chapter 7




    第八章 回溯法

    Chapter 8




    第九章 图遍历

    Chapter 9




    第十章 图算法

    Chapter 10




    第十一章 动态规划

    Chapter 11




    第十二章 网络

    Chapter 12




    第十三章 几何

    Chapter 13




    第十四章 计算几何

    Chapter 14





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  • 原文地址:https://www.cnblogs.com/cyendra/p/3681609.html
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