Codeforces Round #247 (Div. 2) B

B. Shower Line

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

Many students live in a dormitory. A dormitory is a whole new world of funny amusements and possibilities but it does have its drawbacks.

There is only one shower and there are multiple students who wish to have a shower in the morning. That's why every morning there is a line of five people in front of the dormitory shower door. As soon as the shower opens, the first person from the line enters the shower. After a while the first person leaves the shower and the next person enters the shower. The process continues until everybody in the line has a shower.

Having a shower takes some time, so the students in the line talk as they wait. At each moment of time the students talk in pairs: the (2i - 1)-th man in the line (for the current moment) talks with the (2i)-th one.

Let's look at this process in more detail. Let's number the people from 1 to 5. Let's assume that the line initially looks as 23154 (person number 2 stands at the beginning of the line). Then, before the shower opens, 2 talks with 3, 1 talks with 5, 4 doesn't talk with anyone. Then 2 enters the shower. While 2 has a shower, 3 and 1 talk, 5 and 4 talk too. Then, 3 enters the shower. While 3 has a shower, 1 and 5 talk, 4 doesn't talk to anyone. Then 1 enters the shower and while he is there, 5 and 4 talk. Then 5 enters the shower, and then 4 enters the shower.

We know that if students i and j talk, then the i-th student's happiness increases by g_ij and the j-th student's happiness increases by g_ji. Your task is to find such initial order of students in the line that the total happiness of all students will be maximum in the end. Please note that some pair of students may have a talk several times. In the example above students 1 and 5 talk while they wait for the shower to open and while 3 has a shower.

Input

The input consists of five lines, each line contains five space-separated integers: the j-th number in the i-th line shows g_ij (0 ≤ g_ij ≤ 10⁵). It is guaranteed that g_ii = 0 for all i.

Assume that the students are numbered from 1 to 5.

Output

Print a single integer — the maximum possible total happiness of the students.

Sample test(s)

Input

0 0 0 0 9
0 0 0 0 0
0 0 0 0 0
0 0 0 0 0
7 0 0 0 0

Output

32

Input

0 43 21 18 2
3 0 21 11 65
5 2 0 1 4
54 62 12 0 99
87 64 81 33 0

Output

620

题目大意：输出最大的欢乐值。

思路：要输出最大的欢乐值，应该枚举全部的情况，找出最大的欢乐值，数据较小能够枚举。

#include<iostream>
#include<cstring>
#include<cstdio>
#include<string>
#include<cmath>
#include<algorithm>
#define LL int
#define inf 0x3f3f3f3f
using namespace std;
int a[6][6];
int f[]={0,1,2,3,4};
bool bj;
int main()
{
    LL n,m,i,j,k,l;
    LL a1,a2,a3,a4;
        for(i=0;i<5;i++)
        {
            for(j=0;j<5;j++)
            {
                scanf("%d",&a[i][j]);
            }
        }
        for(i=0;i<4;i++)
        {
            for(j=i+1;j<5;j++)
            {
                a[i][j]=a[j][i]=a[i][j]+a[j][i];//枚举出全部可能的欢乐值
            }
        }
        LL ans=0;
        do//注意运行后推断
        {
            ans=max(ans,a[f[0]][f[1]]*2+a[f[1]][f[2]]*2+a[f[2]][f[3]]+a[f[3]][f[4]]);<span id="transmark"></span>
        }
        while(next_permutation(f,f+5))//注意排序问题。由于数组从0下标開始，若为1则不能够这么写
        printf("%d
",ans);
    return 0;
}