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  • LeetCode 227. Basic Calculator II(后缀表达式)

    题目

    后缀表达式一把嗦。

    class Solution {
    public:
        int s1[1000005];
        int s2[1000005];
        int s3[1000005];
        int top1;
        int top2;
        int top3;
        int calculate(string s) {
            
            top1=0;top2=0;top3=0;
            string str="";
            for(int i=0;i<s.length();i++)
            {
                if(s[i]>='0'&&s[i]<='9')
                {
                    str+=s[i];
                    continue;
                }
                
                if(str!="")
                {
                    s2[top2++] = atoi(str.c_str());
                    str="";
                }
                if(s[i]==' ') continue;
                
                if(s[i]=='+'||s[i]=='-'||s[i]=='*'||s[i]=='/')
                {
                    if(top1==0)
                    {
                        s1[top1++]=change(s[i]);
                    }
                    else
                    {
                        while(top1>=1&&judge(change2(s1[top1-1]),s[i]))
                        {
                            
                            s2[top2++]=s1[top1-1];
                            top1--;
                        }
                        s1[top1++]=change(s[i]);
                    } 
                }
            }
            
            if(str!="")
                s2[top2++]=atoi(str.c_str());
            
            while(top1!=0)
            {
                s2[top2++]=s1[top1-1];
                top1--;
            }
            
            for(int i=0;i<top2;i++)
            {
                if(s2[i]==-1)
                {
                    int x =s3[top3-2]/s3[top3-1];
                    top3-=2;
                    s3[top3++]=x;
                }
                else if(s2[i]==-2)
                {
                    int x =s3[top3-2]*s3[top3-1];
                    top3-=2;
                    s3[top3++]=x;
                }
                
                else if(s2[i]==-3)
                {
                    int x =s3[top3-2]-s3[top3-1];
                    top3-=2;
                    s3[top3++]=x;
                }
                
                 else if(s2[i]==-4)
                {
                    int x =s3[top3-2]+s3[top3-1];
                    top3-=2;
                    s3[top3++]=x;
                }
                else
                {
                    s3[top3++]=s2[i];
                }
            }
            
            return s3[0];
            
        }
        
        int change(char x)
        {
            if(x=='+')
                return -4;
            else if(x=='-')
                return -3;
            else if(x=='*')
                return -2;
            else
                return -1;
        }
        
        char change2(int x)
        {
            if(x==-1)
                return '/';
            else if(x==-2)
                return '*';
            else if(x==-3)
                return '-';
            else
                return '+';
            
        }
        
        int judge(char x,char y)
        {
            if(x=='+'||x=='-')
            {
                if(y=='+'||y=='-')
                    return 1;
                if(y=='*'||y=='/')
                    return 0;
            }
            
            if(x=='*'||x=='/')
            {
                if(y=='+'||y=='-')
                    return 1;
                if(y=='*'||y=='/')
                    return 1;
            }
            
            return 0;
        }
    };
    
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  • 原文地址:https://www.cnblogs.com/dacc123/p/12409668.html
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