Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as:
a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
Example 1:
Given the following tree [3,9,20,null,null,15,7]
:
Return true.
Example 2:
Given the following tree [1,2,2,3,3,null,null,4,4]
:
Return false.
判断是否为平衡二叉树
c++
class Solution { public: bool isBalanced(TreeNode* root) { if(root == NULL) return true; bool tagleft=true;bool tagright=true; int dleft=0;int dright=0; if(root->left!=NULL) tagleft = isBalanced(root->left); if(root->right!=NULL) tagright = isBalanced(root->right); if(root->left!=NULL) dleft = deep(root->left); if(root->right!=NULL) dright = deep(root->right); if(tagleft&&tagright&&abs(dleft-dright)<=1) return true; else return false; } int deep(TreeNode* root) { int dleft=0;int dright=0; if(root->left!=NULL) dleft = deep(root->left); if(root->right!=NULL) dright = deep(root->right); return max(dleft,dright)+1; } };