B

In this problem you need to make a multiply table of N * N ,just like the sample out. The element in the i ^th row and j ^th column should be the product(乘积) of i and j.

InputThe first line of input is an integer C which indicate the number of test cases.

Then C test cases follow.Each test case contains an integer N (1<=N<=9) in a line which mentioned above.
OutputFor each test case, print out the multiply table.
Sample Input

2
1
4

Sample Output

1
1 2 3 4
2 4 6 8
3 6 9 12
4 8 12 16



这是一道水题，但是一道水题还是有东西的，比如这个其实是数学上的一个技巧，emmm，具体是什么我忘了，但是这个方法可以变形的。
这个方法可以解决概率等一些抽象的数学问题，反正就是将抽象化的直观的解题手段（在数学上）


#include<iostream>
using namespace std;
int main()
{
	int datanum;
	cin >> datanum;
	while (datanum--)
	{
		int num;
		cin >> num;
		for (int i = 1; i <= num; i++)
		{
			for (int j = 1; j <= num; j++)
			{
				cout << i*j;
				if (j < num) cout << " ";
			}
			cout << endl;
		}
	}
	return 0;
}