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  • P1074 靶形数独(TLE 75)

    题目

    #include<iostream>
    #include<cstdio>
    #include<algorithm>
    #include<cstring>
    #include<string>
    #include<cmath>
    #define LL long long
    using namespace std;
    int lief[10][10],hangf[10][10],gef[10][10];
    int quan[10][10]=
    {
      0,0,0,0,0,0,0,0,0,0,
      0,6,6,6,6,6,6,6,6,6,
      0,6,7,7,7,7,7,7,7,6,
      0,6,7,8,8,8,8,8,7,6,
      0,6,7,8,9,9,9,8,7,6,
      0,6,7,8,9,10,9,8,7,6,
      0,6,7,8,9,9,9,8,7,6,
      0,6,7,8,8,8,8,8,7,6,
      0,6,7,7,7,7,7,7,7,6,
      0,6,6,6,6,6,6,6,6,6,
    };
    int ge[10][10]=
    {
      0,0,0,0,0,0,0,0,0,0,
      0,1,1,1,2,2,2,3,3,3,
      0,1,1,1,2,2,2,3,3,3,
      0,1,1,1,2,2,2,3,3,3,
      0,4,4,4,5,5,5,6,6,6,
      0,4,4,4,5,5,5,6,6,6,
      0,4,4,4,5,5,5,6,6,6,
      0,7,7,7,8,8,8,9,9,9,
      0,7,7,7,8,8,8,9,9,9,
      0,7,7,7,8,8,8,9,9,9,
    };
    int a[10][10];
    int sum=0,sum2;
    void dfs(int x,int y,int tot)
    {
        if(x==10&&y==1){
            sum=max(sum,tot);
            return;
        }
        if(a[x][y]){
            if(y<9) dfs(x,y+1,tot);
            else dfs(x+1,1,tot);
        }
        else{
            for(int i=1;i<=9;i++){
                if( !lief[y][i] && !hangf[x][i]&& !gef[ge[x][y]][i]) {
                lief[y][i]=1,hangf[x][i]=1,gef[ge[x][y]][i]=1,a[x][y]=i;
                if(y<9) dfs(x,y+1,tot+i*quan[x][y]);
                else    dfs(x+1,1,tot+i*quan[x][y]);
                lief[y][i]=0,hangf[x][i]=0,gef[ge[x][y]][i]=0,a[x][y]=0;
                }
    
            }
    
        }
    }
    int main()
    {
        for(int i=1;i<=9;i++)
         for(int j=1;j<=9;j++){
            scanf("%d",&a[i][j]);
            sum+=quan[i][j]*a[i][j];
            lief[j][a[i][j]]=1;
            hangf[i][a[i][j]]=1;
            gef[ge[i][j]][a[i][j]]=1;
         }
        sum2=sum;
        dfs(1,1,sum);
        if(sum2==sum) printf("-1");
        else 
        printf("%d",sum);
        return 0;  
    }
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  • 原文地址:https://www.cnblogs.com/dfsac/p/6819782.html
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