Given a string s consists of upper/lower-case alphabets and empty space characters ' '
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World"
,
return 5
.
思路:遇到空格并且下一个字符不是空格或者‘’ ,len 清零,否则++;
class Solution { public: int lengthOfLastWord(const char *s) { const char *p = s; int len = 0; p = s; while(*p != '') { if(*p == ' ') { if(*(p+1) != ' ' && *(p+1) != '') len = 0; } else len ++; p++; } return len; } };