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  • SQL 遍历父子关系表(二叉树)获得所有子节点 所有父节点(转)

    --建立測試環境
    Create Table A
    (ID Int,
     fatherID Int,
     NameVarchar(10)
    )
    Insert A Select 1,        NULL,       'tt'
    Union All Select 2,        1,          'aa'
    Union All Select 3,        1,          'bb'
    Union All Select 4,        2,          'cc'
    Union All Select 5,        2,          'gg'
    Union All Select 6,        4,          'yy'
    Union All Select 7,        4,          'jj'
    Union All Select 8,        7,           'll'
    Union All Select 9,        NULL,  'uu'
    Union All Select 10,       9,         'oo'
    GO
    --建立函數

    --取字子节点
    Create Function GetChildren(@ID Int)
    Returns @Tree Table (ID Int, fatherID Int, Name Varchar(10))
    As
    Begin
    Insert @Tree Select ID, fatherID, Name From A Where fatherID = @ID
    While @@Rowcount > 0
    Insert @Tree Select A.ID, A.fatherID, A.Name From A A Inner Join @Tree B On A.fatherID = B.ID And A.ID Not In (Select ID From @Tree)
    Return
    End
    GO

    --取父节点

    set ANSI_NULLS ON
    set QUOTED_IDENTIFIER ON
    GO
    Create Function [dbo].[GetParent](@ID Int)
    Returns @Tree Table (ID Int, fatherID Int, Name Varchar(10))
    As
    Begin
    Insert @Tree Select ID, fatherID, Name From A Where ID = @ID
    While @@Rowcount > 0
    Insert @Tree Select A.ID, A.fatherID, A.Name From A A Inner Join @Tree B On A.ID = B.fatherID And A.ID Not In (Select ID From @Tree)
    Return
    End

    --測試
    Select * From dbo.GetChildren(1)

    Select * From dbo.GetParent(9)
    GO

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  • 原文地址:https://www.cnblogs.com/dingding0505/p/3715420.html
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